Classical Dynamics of Particles and Systems
5th Edition
ISBN: 9780534408961
Author: Stephen T. Thornton, Jerry B. Marion
Publisher: Cengage Learning
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The Lagrangian of a particle of mass m moving in one dimension is given by:
L = 12 m x2 – b x
Where b is a positive constant. The coordinate of the particle x (t) at a time t is given by:
A. - b2m t2 + C1 t + C2
B. C1 t + C2
C. C1 Cos (btm) + C2 Sin (btm)
D. C1 Cosh (btm) + Sinh (btm)
show how you got it. All steps must be clearly shown.
Our unforced spring mass model is mx00 + βx0 + kx = 0 with m, β, k >0. We know physically that our spring will eventually come to rest nomatter the initial conditions or the values of m, β, or k. If our modelis a good model, all solutions x(t) should approach 0 as t → ∞. Foreach of the three cases below, explain how we know that both rootsr1,2 =−β ± Sqrt(β^2 − 4km)/2mwill lead to solutions that exhibit exponentialdecay.(a) β^2 − 4km > 0.
(b) β^2 − 4km =0.
(c) β^2 − 4km >= 0.
For Problem 9.13, how do I appropriately answer this?
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