Chapter 8.6, Problem 8.10PP

Interpretation Introduction

(a)

Interpretation:

The molarity of $\text{NaCl}$ solution when $1\text{ mol}$ is present in $0.5\text{ L}$ is to be determined.

Concept introduction:

The formula to calculate molarity is given as follows:

  $\text{Molarity}\left(\text{mol/L}\right)=\frac{\text{number of moles}}{\text{volume}\left(\text{L}\right)}$

Interpretation Introduction

(b)

Interpretation:

The molarity of $\text{NaCl}$ solution when $\text{0}\text{.050 mol}$ is present in $\text{5}\text{.0 mL}$ aqueous solution is to be determined.

Concept introduction:

The formula to calculate molarity isgiven as follows:

  $\text{Molarity}\left(\text{mol/L}\right)=\frac{\text{number of moles}}{\text{volume}\left(\text{L}\right)}$

The conversion factor to convert $\text{L}$ to $\text{mL}$ is given as follows:

  $1\text{ L}={\text{10}}^3\text{ mL}$

Interpretation Introduction

(c)

Interpretation:

The molarity of $\text{NaCl}$ solution when $24.4\text{ g}$ is present in $\text{350 mL}$ aqueous solution is to be calculated.

Concept introduction:

The formula to calculate molarity is given as follows:

  $\text{Molarity}\left(\text{mol/L}\right)=\frac{\text{number of moles}}{\text{volume}\left(\text{L}\right)}$

The formula to calculate the number of moles is given as follows:

  $\text{Number of moles}=\frac{\text{given mass}\left(\text{g}\right)}{\text{molar mass}\left(\text{g/mol}\right)}$

Interpretation Introduction

(d)

Interpretation:

The molarity of $\text{NaCl}$ solution when $2\text{ mol}\text{}\text{NaCl}$ is present in $\text{250 mL}$ aqueous solution is to be calculated.

Concept introduction:

The formula to calculate molarity is given as follows:

  $\text{Molarity}\left(\text{mol/L}\right)=\frac{\text{number of moles}}{\text{volume}\left(\text{L}\right)}$

Interpretation Introduction

(e)

Interpretation:

The molarity of $\text{NaCl}$ solution when $\text{12 g}$ is present in $2\text{ L}$ aqueous solution is to be calculated.

Concept introduction:

The formula to calculate molarity is,

  $\text{Molarity}\left(\text{mol/L}\right)=\frac{\text{number of moles}}{\text{volume}\left(\text{L}\right)}$

Interpretation Introduction

(f)

Interpretation:

The molarity of $\text{NaCl}$ solution when $\text{60 g}$ is present in $750\text{ mL}$ aqueous solution is to be calculated.

Concept introduction:

The formula to calculate molarity is,

  $\text{Molarity}\left(\text{mol/L}\right)=\frac{\text{number of moles}}{\text{volume}\left(\text{L}\right)}$

The expression to calculate the number of moles is given as follows:

  $\text{Number of moles}=\frac{\text{given mass}\left(\text{g}\right)}{\text{molar mass}\left(\text{g/mol}\right)}$