University Physics Volume 2
18th Edition
ISBN: 9781938168161
Author: OpenStax
Publisher: OpenStax
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Chapter 13, Problem 19CQ
Is the work required to accelerate a rod from rest to a speed v in a magnetic field greater than the final kinetic energy of the rod? Why?
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University Physics Volume 2
Ch. 13 - Chek sour Understanding A closely und coil has a...Ch. 13 - Check ‘sour Und.rtanding Find the dhectlon of the...Ch. 13 - Check Your UnderstAnding Verify the directions of...Ch. 13 - Check Your Understanding Shown below is a rod of...Ch. 13 - Check Your Understanding A rod of length 10cm...Ch. 13 - Check Your understanding Suppose that the coil of...Ch. 13 - Check Your Understanding What Is the magnitude of...Ch. 13 - Check your Understanding Themagneticfield shown...Ch. 13 - Check Your Understanding A long solenoid of...Ch. 13 - A stationary coil is in a magnetic field that is...
Ch. 13 - In Faraday’s experiments, what would be the...Ch. 13 - A copper ring and a wooden ring of the same...Ch. 13 - Discuss the factors determining the induced emf in...Ch. 13 - a. Does the induced emf in a circuit depend on the...Ch. 13 - How would changing the radius of loop D shown...Ch. 13 - Can there be an induced emf in a circuit at an...Ch. 13 - Does the induced emf always act to decrease the...Ch. 13 - How would you position a flat loop of wire in a...Ch. 13 - The normal to tt plane of a single-turn conducting...Ch. 13 - The circular conducting loops shown in the...Ch. 13 - The north pole of a mag’iet is moved toward a...Ch. 13 - The accompanying figure shows a conducting ring at...Ch. 13 - Show that and dm/dt have the same units.Ch. 13 - State the direction of the induced current for...Ch. 13 - A bar magnet falls under the influence of gravity...Ch. 13 - Around the geographic North Pole (or magnetic...Ch. 13 - A wire loop moves translationally (no rotation) in...Ch. 13 - Is the work required to accelerate a rod from rest...Ch. 13 - The copper sheet shown below is partially in a...Ch. 13 - A conducting sheet lies in a plane perpendicular...Ch. 13 - Electromagnetic braking can be achieved by...Ch. 13 - A coil is moved through a magnetic field as shown...Ch. 13 - A 50-turn coil has a diameter of 15 cm. The coil...Ch. 13 - Repeat your calculations of the preceding...Ch. 13 - A square loop whose sides are 6.0-cm long is made...Ch. 13 - The magnetic field through a circular loop of...Ch. 13 - The accompanying figure shows a single-turn...Ch. 13 - How would the answers to the preceding problem...Ch. 13 - A long solenoid with n= 10 turns per centimeter...Ch. 13 - A rectangular wire loop with length a and width b...Ch. 13 - The magnetic field perpendicular to a single sire...Ch. 13 - A single-turn circular loop of wire of radius 50...Ch. 13 - When a magnetic field is first turned on, t1 flux...Ch. 13 - The magnetic flux through the loop shown in the...Ch. 13 - Use Lenz’s law to determine tl direction of...Ch. 13 - An automobile with a radio antenna 1.0 m long...Ch. 13 - Prob. 38PCh. 13 - Suppose the magnetic field of the preceding...Ch. 13 - A coil of 1000 turns encloses an area of 25 cm2....Ch. 13 - In the circuit sho in the accompanying figure, the...Ch. 13 - The rod shown in the accompanying figure is moving...Ch. 13 - A 25-cm nod moves at 5.0 m/s in a plane...Ch. 13 - In the accompanying figure, the rails, connecting...Ch. 13 - The rod shown below moves to the right on...Ch. 13 - Shown below is a conducting rod that slides along...Ch. 13 - Calculate the induced electric field in a 50-tuni...Ch. 13 - The magnetic field through a circular loop of...Ch. 13 - The current I through a long solenoid with n trims...Ch. 13 - Calculate the electric field induced both inside...Ch. 13 - Prob. 51PCh. 13 - The magnetic field at all points within the...Ch. 13 - The current in a long solenoid of radius 3 cm is...Ch. 13 - The current in a long solenoid of radius 3 cm and...Ch. 13 - Design a current loop that, when rotated in a...Ch. 13 - A flat, square coil of 20 turns that has sides of...Ch. 13 - A 50-turn rectangular coil with dimensions...Ch. 13 - The square armature coil of an alternating current...Ch. 13 - A flip coil is a relatively simple device used to...Ch. 13 - The flip coil of the preceding problem has a...Ch. 13 - A 120-V, series-wound motor has a field resistance...Ch. 13 - A small series-wound dc motor is operated from a...Ch. 13 - Shown in the following figure is a long, straight...Ch. 13 - A metal bar of mass 500 g slides outward at a...Ch. 13 - A current is induced in a circular loop of radius...Ch. 13 - A metal bar of length 25 cm is placed...Ch. 13 - A coil with 50 turns and area 10cm2 is oriented...Ch. 13 - A 2-turn planer loop of flexible wire is placed...Ch. 13 - The conducting rod shown in the accompanying...Ch. 13 - A circular loop of wire of radius 10 cm is mounted...Ch. 13 - The magnetic field between the poles of a...Ch. 13 - A long solenoid of radius a with n turns per unit...Ch. 13 - A 120-V, series-wound dc motor draws 0.50 A from...Ch. 13 - The armature and field coils of a series-wound...Ch. 13 - A copper wire of Length I is fashioned into a...Ch. 13 - A 0.50-kg copper sheet drops through a uniform...Ch. 13 - A circular copper disk of radius 7.5 on rotates at...Ch. 13 - A short rod of length a moves with its velocity...Ch. 13 - A rectangular circuit containing a resistance R is...Ch. 13 - Two infinite solenoids cross the plane of the...Ch. 13 - An eight-turn coil is tightly wrapped around the...Ch. 13 - Shown below is a long rectangular loop of width w,...Ch. 13 - A square bar of mass m and resistance R is sliding...Ch. 13 - The accompanying figure shows a metal disk of...Ch. 13 - A long solenoid with 10 turns per centimeter is...Ch. 13 - The current in the long, straight wire shown in...Ch. 13 - A 500-turn coil with a 0.250m2 area is spun in...Ch. 13 - A circular loop of wire of radius 10 cm. is...Ch. 13 - A long solenoid of radius a with n turns per unit...Ch. 13 - A rectangular copper loop of mass 100 g and...Ch. 13 - A metal bar of mass m slides without friction over...Ch. 13 - A time-dependent uniform magnetic field of...
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- Does increasing the magnitude of a uniform magnetic field through which a charge is traveling necessarily mean increasing the magnetic force on the charge? Does changing the direction of the field necessarily mean a change in the force on the charge?arrow_forwardShow that the magnetic field at a distance r from the axis of two circular parallel plates, produced by placing charge Q(t) on the plates is Bind=02rdQ(t)dtarrow_forwardA cosmic-ray proton in interstellar space has an energy of 10.0 MeV and executes a circular orbit having a radius equal to that of Mercury’s orbit around the Sun (5.80 × 1010 m). What is the magnetic field in that region of space?arrow_forward
- A proton moving in the plane of the page has a kinetic energy of 6.00 MeV. A magnetic field of magnitude H = 1.00 T is directed into the page. The proton enters the magnetic field with its velocity vector at an angle = 45.0 to the linear boundary of' the field as shown in Figure P29.80. (a) Find x, the distance from the point of entry to where the proton will leave the field. (b) Determine . the angle between the boundary and the protons velocity vector as it leaves the field.arrow_forwardIs Ampere’s law valid for all closed paths? Why isn’t it normally useful for calculating a magnetic field?arrow_forwardWhy is the following situation impossible? Figure P28.46 shows an experimental technique for altering the direction of travel for a charged particle. A particle of charge q = 1.00 C and mass m = 2.00 1015 kg enters the bottom of the region of uniform magnetic field at speed = 2.00 105 m/s, with a velocity vector perpendicular to the field lines. The magnetic force on the particle causes its direction of travel to change so that it leaves the region of the magnetic field at the top traveling at an angle from its original direction. The magnetic field has magnitude B = 0.400 T and is directed out of the page. The length h of the magnetic field region is 0.110 m. An experimenter performs the technique and measures the angle at which the particles exit the top of the field. She finds that the angles of deviation are exactly as predicted. Figure P28.46arrow_forward
- A cosmic-ray electron moves at 7.5 × 106 m/sinches perpendicular to Earth’s magnetic field at an altitude queer the field strength is 1.0 × 105T. What is the radius of the circular path the electron follows?arrow_forwardHow many turns must be wound on a flat, circular coil of radius 20 cm in order to produce a magnetic field of magnitude 4.0105 T at the center of the coil when the current through it is 0.85 A?arrow_forwardWhen the current through a circular loop is 6.0 A, the magnetic field at its center is 2.0104 T. What is the radius of the loop?arrow_forward
- Electrons in Earths upper atmosphere have typical speeds near 6.00 105 m/s. (a) Calculate the magnitude of Earths magnetic field if an electrons velocity is perpendicular to the magnetic field and its circular path has a radius of 7.00 102 m. (b) Calculate the number of times per second that an electron circles around a magnetic field line.arrow_forwardThe strengths of the fields in the velocity selector of a Bainbridge mass spectrometer are B = 0.500 T and E=1.2105 Van, and tire strength of the magnetic field that separates the ions is Bo=0.750 T. A stream of singly charged Li ions is found to bend in a circular arc of radius 2.32 cm. What is the mass of the Li ions?arrow_forwardCheck Your Understanding Repeat the previous problem with the magnetic field in the x-direction rather than in the z-direction. Check your answers with RHR-1.arrow_forward
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