General Physics, 2nd Edition
General Physics, 2nd Edition
2nd Edition
ISBN: 9780471522782
Author: Morton M. Sternheim
Publisher: WILEY
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Chapter 18, Problem 1RQ
To determine

Comparing between telephone cable and an axon.

Expert Solution & Answer
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Answer to Problem 1RQ

Compared to a telephone cable, an axon has much more resistance, is much more poorly insulated, and needs much more frequent amplification.

Explanation of Solution

Write the expression or the resistance of the axoplasm

R=ρ0lπr2        (I)

Here, R is the resistance, ρ0 is the resistivity, l is the length, r is the radius.

Conclusion:

Substitute, 2Ω-m for ρ0, 1cm for l, 2μm for r in equation (I) to find R.

R=(2Ω-m)[(1cm)(1×102m1cm)]π[(2μm)(1×106m1μm)]2=1.59×109Ω

Here. The resistance of axon is equal to the resistance of telephone cable which contains 70 km of number 40 copper wire.

Thus, Compared to a telephone cable, an axon has much more resistance, is much more poorly insulated, and needs much more frequent amplification.

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Students have asked these similar questions
Calculate the axoplasm resistance for a neuron of length 0.06 m and a radius of 5 um. The axoplasm resistivity is 2.0 Ohm.m. Give your answer in MOhms
The velocity of spike propagation is proportional to the following combination of factors: 1 a C, V R„R, m Where a is the radius of the axon, Rm and R; are specific resistances of the membrane and the internal buffer, respectively. If we double the radius and simultaneously increase the concentration of salt inside the axon twice (i.e. R; decreases two times), by how many fold will the velocity change?
Assume an axon has the same characteristics as the class example except the radius of the axon is 0.005 mm and the membrane thickness is 20.0 nm. The percentage fractional change in the concentration of Na+ ions in the axon during one action potential is %? Record the answer to the nearest one thousandth.
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