Manufacturing Processes for Engineering Materials (6th Edition)
6th Edition
ISBN: 9780134290553
Author: Serope Kalpakjian, Steven Schmid
Publisher: PEARSON
expand_more
expand_more
format_list_bulleted
Question
Chapter 2, Problem 2.39Q
To determine
Whether the material have negative Poisson’s ratio or not.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
The lower yield point for a certain plain carbon steelbar is found to be 135 MPa, while a second bar of the samecomposition yields at 260 MPa. Metallographic analysisshows that the average grain diameter is 50μm in the firstbar and 8μm in the second bar.a. Predict the grain diameter needed to cause a loweryield point of 205 MPa.b. If the steel could be fabricated to form a stablegrain structure of 500 nm grains, what strengthwould be predicted?c. Why might you expect the upper yield point to bemore alike in the first two bars than the lower yieldpoint?
Question 1
You are working on a design team at a small orthopaedic firm. You have been asked to select a cobalt-
chrome-molybdenum (CoCr) material that will not experience plastic deformation under a specific mechanical test, as follows...
A tensile stress is applied along the long axis of a solid cylindrical rod that has a diameter of 10 mm. An applied load of some
magnitude F produces a 7x10³ mm change in diameter (see figure below, original shape is blue, elongated shape is unshaded).
Q1F: How would the "new alloy" material (with different properties as shown below) behave, assuming it has the same initial
diameter (10mm) and applied load (F) in the tensile test? That is, would it experience plastic deformation (yield) under the
conditions of this problem?
The lower yield point for a certain plain carbon steel bar is found to be 135 MPa, while a second bar of the same composition yields at 260 MPa. Metallographic analysis shows that the average grain diameter is 50 µm in the first bar and 8 µm in the second bar. Predict the grain diameter needed to cause a lower yield point of 205 MPa.
Chapter 2 Solutions
Manufacturing Processes for Engineering Materials (6th Edition)
Ch. 2 - Prob. 2.1QCh. 2 - Prob. 2.2QCh. 2 - Prob. 2.3QCh. 2 - Prob. 2.4QCh. 2 - Prob. 2.5QCh. 2 - Prob. 2.6QCh. 2 - Prob. 2.7QCh. 2 - Prob. 2.8QCh. 2 - Prob. 2.9QCh. 2 - Prob. 2.10Q
Ch. 2 - Prob. 2.11QCh. 2 - Prob. 2.12QCh. 2 - Prob. 2.13QCh. 2 - Prob. 2.14QCh. 2 - Prob. 2.15QCh. 2 - Prob. 2.16QCh. 2 - Prob. 2.17QCh. 2 - Prob. 2.18QCh. 2 - Prob. 2.19QCh. 2 - Prob. 2.20QCh. 2 - Prob. 2.21QCh. 2 - Prob. 2.22QCh. 2 - Prob. 2.23QCh. 2 - Prob. 2.24QCh. 2 - Prob. 2.25QCh. 2 - Prob. 2.26QCh. 2 - Prob. 2.27QCh. 2 - Prob. 2.28QCh. 2 - Prob. 2.29QCh. 2 - Prob. 2.30QCh. 2 - Prob. 2.31QCh. 2 - Prob. 2.32QCh. 2 - Prob. 2.33QCh. 2 - Prob. 2.34QCh. 2 - Prob. 2.35QCh. 2 - Prob. 2.36QCh. 2 - Prob. 2.37QCh. 2 - Prob. 2.38QCh. 2 - Prob. 2.39QCh. 2 - Prob. 2.40QCh. 2 - Prob. 2.41QCh. 2 - Prob. 2.42QCh. 2 - Prob. 2.43QCh. 2 - Prob. 2.44QCh. 2 - Prob. 2.45QCh. 2 - Prob. 2.46QCh. 2 - Prob. 2.47QCh. 2 - Prob. 2.48QCh. 2 - Prob. 2.49PCh. 2 - Prob. 2.50PCh. 2 - Prob. 2.51PCh. 2 - Prob. 2.52PCh. 2 - Prob. 2.53PCh. 2 - Prob. 2.54PCh. 2 - Prob. 2.55PCh. 2 - Prob. 2.56PCh. 2 - Prob. 2.57PCh. 2 - Prob. 2.58PCh. 2 - Prob. 2.59PCh. 2 - Prob. 2.60PCh. 2 - Prob. 2.61PCh. 2 - Prob. 2.62PCh. 2 - Prob. 2.63PCh. 2 - Prob. 2.64PCh. 2 - Prob. 2.65PCh. 2 - Prob. 2.66PCh. 2 - Prob. 2.67PCh. 2 - Prob. 2.68PCh. 2 - Prob. 2.69PCh. 2 - Prob. 2.70PCh. 2 - Prob. 2.71PCh. 2 - Prob. 2.72PCh. 2 - Prob. 2.73PCh. 2 - Prob. 2.74PCh. 2 - Prob. 2.75PCh. 2 - Prob. 2.76PCh. 2 - Prob. 2.78PCh. 2 - Prob. 2.79PCh. 2 - Prob. 2.80PCh. 2 - Prob. 2.81PCh. 2 - Prob. 2.82PCh. 2 - Prob. 2.83PCh. 2 - Prob. 2.84PCh. 2 - Prob. 2.85PCh. 2 - Prob. 2.86PCh. 2 - Prob. 2.87PCh. 2 - Prob. 2.88PCh. 2 - Prob. 2.89PCh. 2 - Prob. 2.90PCh. 2 - Prob. 2.91PCh. 2 - Prob. 2.92PCh. 2 - Prob. 2.93PCh. 2 - Prob. 2.94PCh. 2 - Prob. 2.95PCh. 2 - Prob. 2.96PCh. 2 - Prob. 2.97PCh. 2 - Prob. 2.98PCh. 2 - Prob. 2.99PCh. 2 - Prob. 2.100PCh. 2 - Prob. 2.101P
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.Similar questions
- Q3 contd. (d) The yield strength values of pure aluminium (Al) and pure copper (Cu) are 25 MPa and 20 MPa, respectively; whereas the yield strength values of cold rolled Al-Mn-Mg alloy and cast 60-40 Brass (60% Cu, 40% Zn) are 200 MPa and 105 MPa, respectively. With aid of schematics, explain the main mechanisms account for the increases in the strengths. (e) A cylindrical tie rod with a diameter of 18.4 mm is subjected to cyclic loading. The stress range is +/- 200 kN. Figure Q3.3 shows the S-N curve of the material of which the rod is made, how many cycles will this rod survive? Stress amplitude O₂ (MPa) 1500 1400 1300 1200 1100 1000 900 800 700 600 500 400 10² 10³ 104 4340 low-alloy steel Stress ratio = -1 Fig. Q3.3 105 106 Number of cycles to failure, Nf 107 108arrow_forwardQuestion 1 You are working on a design team at a small orthopaedic firm. You have been asked to select a cobalt- chrome-molybdenum (CoCr) material that will not experience plastic deformation under a specific mechanical test, as follows... A tensile stress is applied along the long axis of a solid cylindrical rod that has a diameter of 10 mm. An applied load of some magnitude F produces a 7x10-³ mm change in diameter (see figure below, original shape is blue, elongated shape is unshaded). Q1A-B: Calculate the transverse strain in the x-direction (Ex) associated with the reduction in diameter. Calculate the axial strain in the z-direction (₂) associated with the length increase.arrow_forwardIf you have a material that is initially hard and strong, would you expect it to cyclically harden or soften? What would be a way of characterizing how strong it must be initially to make your answer a bit more quantitative?arrow_forward
- 3. A 30-cm long, 12-mm diameter carbon steel rod was subjected to 15,5 kN of tension. Calculate (a) the stress and strain in the rod, (b) the amount that it stretches, (c) its change in diameter, and (d) its stiffness (k=EA/L). (e) If the force was only 4.5 kN, by what amount would the rod have stretched?arrow_forward(a) Poisson's ratio for any mechanical component used in Explain the importance industry. Use a suitable example. (b) Describe (briefly) the step by step process used to calculate the Thermal stress and strain for any mechanical component. Use a suitable example.arrow_forwardThe minimum yield strength for iron with an average grain size of 6x10^-2 mm is 135 MPa, this increases to 260 MPa when the average grain size is reduced to 8x10^-3 mm.What must the average grain size be to achieve a yield strength of 205 MPa.arrow_forward
- Describe the behavior of materials under shear stress?arrow_forwardFigure 6.22 shows the tensile engineering stress– strain behavior for a steel alloy. (a) What is the modulus of elasticity? (b) What is the proportional limit? (c) What is the yield strength at a strain offset of 0.002? (d) What is the tensile strength?arrow_forwardWhich materials, behave in the opposite way? Give some examples?arrow_forward
- What is G-P zone? Draw yield stress vs. aging time, use a simple sketch andexplain the mechanism. Why does yield stress change by aging time ?arrow_forwardA batch of casted mild steel has a modulus of elasticity of 200 GPa and a yield strength of 250MPa. Calculate for its modulus of resilience. After cold working the steel, the yield strength increases to 310 MPa. Calculate for the percent reduction in the average grain diameter given σo =70 MPa and k = 0.74.arrow_forwardEstimate the linear relationship between the Ultimate Tensile Strength and HBN for the range of brass alloy shown in Figure 4b (ii).arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Elements Of ElectromagneticsMechanical EngineeringISBN:9780190698614Author:Sadiku, Matthew N. O.Publisher:Oxford University PressMechanics of Materials (10th Edition)Mechanical EngineeringISBN:9780134319650Author:Russell C. HibbelerPublisher:PEARSONThermodynamics: An Engineering ApproachMechanical EngineeringISBN:9781259822674Author:Yunus A. Cengel Dr., Michael A. BolesPublisher:McGraw-Hill Education
- Control Systems EngineeringMechanical EngineeringISBN:9781118170519Author:Norman S. NisePublisher:WILEYMechanics of Materials (MindTap Course List)Mechanical EngineeringISBN:9781337093347Author:Barry J. Goodno, James M. GerePublisher:Cengage LearningEngineering Mechanics: StaticsMechanical EngineeringISBN:9781118807330Author:James L. Meriam, L. G. Kraige, J. N. BoltonPublisher:WILEY
Elements Of Electromagnetics
Mechanical Engineering
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Oxford University Press
Mechanics of Materials (10th Edition)
Mechanical Engineering
ISBN:9780134319650
Author:Russell C. Hibbeler
Publisher:PEARSON
Thermodynamics: An Engineering Approach
Mechanical Engineering
ISBN:9781259822674
Author:Yunus A. Cengel Dr., Michael A. Boles
Publisher:McGraw-Hill Education
Control Systems Engineering
Mechanical Engineering
ISBN:9781118170519
Author:Norman S. Nise
Publisher:WILEY
Mechanics of Materials (MindTap Course List)
Mechanical Engineering
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Cengage Learning
Engineering Mechanics: Statics
Mechanical Engineering
ISBN:9781118807330
Author:James L. Meriam, L. G. Kraige, J. N. Bolton
Publisher:WILEY
An Introduction to Stress and Strain; Author: The Efficient Engineer;https://www.youtube.com/watch?v=aQf6Q8t1FQE;License: Standard YouTube License, CC-BY