BIOLOGY
12th Edition
ISBN: 9781260169614
Author: Raven
Publisher: RENT MCG
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Chapter 24, Problem 2A
Summary Introduction
Introduction:
Non coding DNA or junk DNA is a non functional part of the gene that does not code for any protein. It occurs usually in the repetitive sequences of the
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Check out a sample textbook solutionStudents have asked these similar questions
Which of the following statements below is incorrect? *
A. the genetic code is overlapping
B. the genetic code is universal
C. degenerate codon specify the same amino acids
D. the genetic code is triplet
Which protein can break covalent bond? *
A. Helicase
B. Primase
C. SSB
D. DNA gyrase
What is the complementary hnRNA base sequence produced from the DNA base sequence 5' C-T-A-T-A-C 3'? *
A. 3' C-A-T-A-T-C 5'
B. 3' G-A-T-A-T-G 5'
C. 3' G-A-U-A- U-G 5'
D. 3' C-U-A-U-A-G 5'
Which of the following statements concerning the " cloverleaf" shape of tRNA molecules is correct? *
A. four hairpin loops are present
B. three hairpin loops and one open end are present
C. two hairpin loops and two open ends are present…
Which of the following experimental results was NOT evidence that DNA is the genetic molecule rather than proteins?
a.
When a virus was radioactively labelled, and the virus was allowed to infect a bacteria cell, radioactive virus DNA was found inside the bacteria cell while radioactive virus proteins were found outside the cell.
b.
Dead pathogenic bacteria cells combined with living nonpathogenic bacteria cells caused the creation of living pathogenic cells and thus the death of the host animal.
c.
Proteins are a class of macromolecules with the diversity and specificity needed for hereditary material.
d.
Nucleotide bases occur regularly, such that the number of adenines = number of thymines, and the number of guanines = number of cytosines.
For each example:
a. fill in the complimentary DNA strand
b. fill in the correct mRNA bases by transcribing the bottom DNA code
c. fill in the correct tRNA bases
d. translate the MRNA codons to find the correct amino acids
Example #1
5'
3'
(A (A
DNA
MRNA
TRNA
Amino
Acids
Chapter 24 Solutions
BIOLOGY
Ch. 24.1 - Prob. 1LOCh. 24.1 - Prob. 2LOCh. 24.1 - Prob. 3LOCh. 24.2 - Prob. 1LOCh. 24.2 - Prob. 2LOCh. 24.2 - Prob. 3LOCh. 24.2 - Explain why genome size and genome number do not...Ch. 24.3 - Define the terms segmental duplication, genome...Ch. 24.3 - Prob. 2LOCh. 24.4 - Prob. 1LO
Ch. 24.4 - Prob. 2LOCh. 24.5 - Prob. 1LOCh. 24.5 - Prob. 2LOCh. 24.5 - Prob. 3LOCh. 24 - Prob. 1DACh. 24 - Prob. 1IQCh. 24 - Prob. 2IQCh. 24 - Prob. 3IQCh. 24 - Humans and pufferfish diverged from a common...Ch. 24 - Prob. 2UCh. 24 - Prob. 3UCh. 24 - Homologous genes in distantly related organisms...Ch. 24 - All of the following are believed to contribute to...Ch. 24 - What is the fate of most duplicated genes? a. Gene...Ch. 24 - Chimp and human DNA whole-genome sequences differ...Ch. 24 - Prob. 2ACh. 24 - Analyze the conclusion that the Medicago...Ch. 24 - Analyze why an herbicide that targets the...Ch. 24 - The FOX2 gene is associated with speech in human....Ch. 24 - One of the common misconceptions about sequencing...Ch. 24 - How does horizontal gene transfer (HGT) complicate...
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- You are working in the lab and have measured the size of mRNA that has been transcribed from a particular gene in your cell population. The length of the gene in the cells you are working, measured from the start to the stop sequence is 9000 nucleotides. When you measure the RNA, however, the size is only 3000 nucleotides. What do you think happened? O a. Three DNA base pairs code for one RNA nucleotide. b. mRNA does not contain exons. c. There must have been a deletion mutation in the DNA in these cells. Od. The poly-A tail is present in the DNA but not on the mRNA. Oe. RNA splicing occurred, so introns are removed in the mRNA.arrow_forwardConsider the following segment of DNA:5′ GCTTCCCAA 3′3′ CGAAGGGTT 5′Assume that the top strand is the template strand usedby RNA polymerase.a. Draw the RNA transcribed.b. Label its 5′ and 3′ ends.c. Draw the corresponding amino acid chain.d. Label its amino and carboxyl ends.Repeat parts a through d, assuming the bottom strand tobe the template strand.arrow_forwardShown below is diagram of RNA polymerase undergoing the process of transcription: This transcript: O Select one: a. None of these choices is correct. O b. has a sequence complementary to the top strand of the DNA. c. has a sequence identical to the top strand of the DNA. d. has a sequence complementary to the bottom strand of the DNA. e. has a sequence identical to the bottom strand of the DNA. f. It is not possible to determine, because not enough information has been provided. g. More than one of these choices is correct. MacEarrow_forward
- If you repeat the okazaki experiment WITHOUT denaturing DNA, what would be the expected outcome? a. Increased length of RNA primers b. Slowing of fragment maturation O c. No short fragments observed d. All short fragments observed e. Decrease in fragment size over timearrow_forward1) Where in the heck did Class I transposons originate? a DNA mutations. b Bacteria. c Prophages. d Retroviruses. 2) What do you think about humans only having about 22,500 genes but we contain about 100,000 proteins?! a The production of quaternary shape in proteins can contribute to protein variation. b That's the work of the spliceosome! c Post-translation modifications in the Golgi Apparatus are responsible for some of that. d All the answers are correct.arrow_forwardTopoisomerases are enzymes that can: a. join two DNA fragments to become one. b. catalyze conformational change of a protein. c. cut DNA at specific site. d. catalyze the breaking and rejoining of DNA strands which produces DNA that is either more or less superhelical than the original.arrow_forward
- A small section of bacterial DNA template (anti-sense) strand has the following nucleotide sequence: GTT GTG ACG TAA A mutation in the above sequence involved a substitution of a single base, but did not affect the protein produced when the gene involved was transcribed and translated. Which of the following gene sequences could have the mutation described above? a. GTT GTG ACA TAA b. GTT GGG ACG TAA c. GTA GTG ACG TAA d. GTT GTG ACT TAAarrow_forwardWhich of the following statements are NOT true? A. Replication is the process of making DNA and takes place in the nucleus of prokaryotic cells. B. Translation produces a polypeptide that may require additional processing to become a functional protein C. Transcription starts at the promoter of eukaryotic cells and scans until reaches the start codon. D. Splicing results in exons being put together and introns being removedarrow_forwardCertain restriction endonucleases produce cohesive (sticky) ends. This means that they: a. stick tightly to the ends of the DNA they have cut. b. cut both DNA strands at the same base pair. c. make a staggered double-strand cut, leaving ends with a few nucleotides of single-stranded DNA protruding. d. cut in regions of high GC content, leaving ends that can form more hydrogen bonds than ends of high AT content. e. cut in regions of high AT content, leaving ends that can form more hydrogen bonds than ends of high GC content.arrow_forward
- The diagram below shows the result of a hybridization experiment between a eukaryotic mRNA and the template strand of its gene. Which of the following statements is TRUE? a. This gene contains four exons. b. The gene’s exons are visible as unpaired DNA loops protruding from the DNA/RNA hybrid. c. The 5’ end of the RNA strand is on the right side of the drawing. d. A hybrid between a prokaryotic mRNA and its gene would result in a similar image. e. the poly-A tail of the mRNA hybridizes with a poly-T stretch in the DNA.arrow_forward1. How may recombinant DNA molecules be introduced into human cells? a. by splicing the needed genes into a mammalian chromosome using restriction enzymes. b. by adding plasmids to the mammalian cells. c. by using engineered viruses as vectors. d. by using a gene gun. 2. If someone is accused of a crime, investigators can collect his or her DNA to compare the DNA of the cells found at the crime scene. To collect human DNA, investigators often swab the inside of person’s cheek. Just a few human cheek cells contain enough material to perform PCR. In a cell, the nucleus and mitochondria contain DNA that is the starting material for PCR. Identify the 4 components needed to start a PCR reaction (equipment not included)arrow_forward(1) DNA polymerase can only add nucleotides to an available 3' end. Why? a. The enzyme is attracted to the negatively charged phosphate group. b. The phosphate group at the 5' end interferes physically and/or electrically with the elongation process. c. The lagging strand needs to be synthesized more slowly. d. Okazaki fragments are critical to the formation of identical copies of DNA. e. No one knows.arrow_forward
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