Loose Leaf for Engineering Circuit Analysis Format: Loose-leaf
9th Edition
ISBN: 9781259989452
Author: Hayt
Publisher: Mcgraw Hill Publishers
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Question
Chapter 3, Problem 52E
(a)
To determine
Find value of current
(b)
To determine
Find value of voltage
(c)
To determine
Find value of current
(d)
To determine
Find value of current
(e)
To determine
Find value of current
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Problem 3: Question
Consider the circuit diagram below. Given IA = 2.5 mA and Is = 1.25 mA:
a) Find the currents Is2, I2, I3, I4 and I7. State your conclusion as a table of values.
b) What is the voltage drop across R7?
c) If Vab = 2.75 V, what is the value of R5?
ISI
10 mA
IS2
I₁
www
I₂
www
(A)
IA
+
a
13
14
R₁
1₁
www
16
R₁
b
1₂
18
The figure below shows a multiloop circuit. The voltages and resistances in the circuit are: V1 = 10.0 V, V2 = 30.0 V, V3 = 58.0 V, R1 = 125.0 Ω, R2 = 155.0 Ω, R3 = 195.0 Ω. Use these values to answer the questions below. (Use the following as necessary: I1, I2, and I3.)
WikiHow LOGO
(a)
Write the equation for the loop ABHEFGA in the order that you go around the loop.
−I2 (155.0 Ω) −30.0 V + 10.0 V − I1 (125.0 Ω) = 0
+I2 (155.0 Ω) +30.0 V +10.0 V − I1 (125.0 Ω) = 0
+I3 (155.0 Ω) +58.0 V −10.0 V − I2 (155.0 Ω) = 0
−I3 (195.0 Ω) −58.0 V +10.0 V − I1 (155.0 Ω) = 0
(b)
Write the equation for the loop BCKDEHB in the order that you go around the loop.
+I2 (155.0 Ω) +30.0 V +10.0 V − I1 (125.0 Ω) = 0
+I3 (195.0 Ω) −58.0 V + 30.0 V + I2 (155.0 Ω) = 0
+I3 (155.0 Ω) +58.0 V −10.0 V − I2 (155.0 Ω) = 0
−I3 (195.0 Ω) −58.0 V +30.0 V − I1 (155.0 Ω) = 0
(C)
Write the equation for the loop ABCKDEFGA in the order that you go around the loop.
+I3 (155.0 Ω) +30.0 V −58.0 V − I2…
Refer to the given circuit below. Determine the mesh current Ic.
R₁
R2
502
50
R₁
E₁
R3
8 Ω
R4
402
R₂
R3
E₂
R5
80
R₁.
Ic
E₁
11 V
E2
10 V
1₁
R5
I
3 A
Chapter 3 Solutions
Loose Leaf for Engineering Circuit Analysis Format: Loose-leaf
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