EBK MANUFACTURING PROCESSES FOR ENGINEE
6th Edition
ISBN: 9780134425115
Author: Schmid
Publisher: YUZU
expand_more
expand_more
format_list_bulleted
Concept explainers
Videos
Question
Chapter 2, Problem 2.37Q
To determine
The effect of increase in
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
A material has the following properties, ultimate Sul = σul = 350mpa, the strain hardening exponent n=0.20. Determine the value for the strength coefficient K.
A circular rod of length 18 cm and diameter 5 mm is made of grade 1045 grade steel.
a. Calculate the stress and strain in the rod, and its extension, when it is subjected to 7 kN of tension.
(Express your answers using three significant figures.)
|MPa
E =
x10-4
(Express your answer using whole numbers.)
AL =
| pm
b. At what force would the rod begin to yield?
(Express your answer using three significant figures.)
F =
|kN
c. By what amount would the rod have to be stretched beyond its original length in order to yield?
(Express your answer using whole numbers.)
AL =
um
1.
A part made of Aluminum 6061-T6 has a yield strength = 400 MPa. For each stress state below, draw all 3 Mohr's circles, find the principal stresses, and calculate the safety factor against yield using both the distortion-energy (von Mises) and maximum shear stress (Tresca) criterions.
(If relevant) A clearly labeled diagram (or diagrams) clearly pertaining to your analysis with a coordinate system and relevant labels.
Final answer with appropriate units and significant figures. You can use the fprintf() command in MATLAB to format numerical results
A 2-3 sentence reflection on your answer. Does it make sense? Why or why not? What are some implications?
Chapter 2 Solutions
EBK MANUFACTURING PROCESSES FOR ENGINEE
Ch. 2 - Prob. 2.1QCh. 2 - Prob. 2.2QCh. 2 - Prob. 2.3QCh. 2 - Prob. 2.4QCh. 2 - Prob. 2.5QCh. 2 - Prob. 2.6QCh. 2 - Prob. 2.7QCh. 2 - Prob. 2.8QCh. 2 - Prob. 2.9QCh. 2 - Prob. 2.10Q
Ch. 2 - Prob. 2.11QCh. 2 - Prob. 2.12QCh. 2 - Prob. 2.13QCh. 2 - Prob. 2.14QCh. 2 - Prob. 2.15QCh. 2 - Prob. 2.16QCh. 2 - Prob. 2.17QCh. 2 - Prob. 2.18QCh. 2 - Prob. 2.19QCh. 2 - Prob. 2.20QCh. 2 - Prob. 2.21QCh. 2 - Prob. 2.22QCh. 2 - Prob. 2.23QCh. 2 - Prob. 2.24QCh. 2 - Prob. 2.25QCh. 2 - Prob. 2.26QCh. 2 - Prob. 2.27QCh. 2 - Prob. 2.28QCh. 2 - Prob. 2.29QCh. 2 - Prob. 2.30QCh. 2 - Prob. 2.31QCh. 2 - Prob. 2.32QCh. 2 - Prob. 2.33QCh. 2 - Prob. 2.34QCh. 2 - Prob. 2.35QCh. 2 - Prob. 2.36QCh. 2 - Prob. 2.37QCh. 2 - Prob. 2.38QCh. 2 - Prob. 2.39QCh. 2 - Prob. 2.40QCh. 2 - Prob. 2.41QCh. 2 - Prob. 2.42QCh. 2 - Prob. 2.43QCh. 2 - Prob. 2.44QCh. 2 - Prob. 2.45QCh. 2 - Prob. 2.46QCh. 2 - Prob. 2.47QCh. 2 - Prob. 2.48QCh. 2 - Prob. 2.49PCh. 2 - Prob. 2.50PCh. 2 - Prob. 2.51PCh. 2 - Prob. 2.52PCh. 2 - Prob. 2.53PCh. 2 - Prob. 2.54PCh. 2 - Prob. 2.55PCh. 2 - Prob. 2.56PCh. 2 - Prob. 2.57PCh. 2 - Prob. 2.58PCh. 2 - Prob. 2.59PCh. 2 - Prob. 2.60PCh. 2 - Prob. 2.61PCh. 2 - Prob. 2.62PCh. 2 - Prob. 2.63PCh. 2 - Prob. 2.64PCh. 2 - Prob. 2.65PCh. 2 - Prob. 2.66PCh. 2 - Prob. 2.67PCh. 2 - Prob. 2.68PCh. 2 - Prob. 2.69PCh. 2 - Prob. 2.70PCh. 2 - Prob. 2.71PCh. 2 - Prob. 2.72PCh. 2 - Prob. 2.73PCh. 2 - Prob. 2.74PCh. 2 - Prob. 2.75PCh. 2 - Prob. 2.76PCh. 2 - Prob. 2.78PCh. 2 - Prob. 2.79PCh. 2 - Prob. 2.80PCh. 2 - Prob. 2.81PCh. 2 - Prob. 2.82PCh. 2 - Prob. 2.83PCh. 2 - Prob. 2.84PCh. 2 - Prob. 2.85PCh. 2 - Prob. 2.86PCh. 2 - Prob. 2.87PCh. 2 - Prob. 2.88PCh. 2 - Prob. 2.89PCh. 2 - Prob. 2.90PCh. 2 - Prob. 2.91PCh. 2 - Prob. 2.92PCh. 2 - Prob. 2.93PCh. 2 - Prob. 2.94PCh. 2 - Prob. 2.95PCh. 2 - Prob. 2.96PCh. 2 - Prob. 2.97PCh. 2 - Prob. 2.98PCh. 2 - Prob. 2.99PCh. 2 - Prob. 2.100PCh. 2 - Prob. 2.101P
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.Similar questions
- In the attached picture there is a sketch of a socket wrench. Assume the wrench is held at a fixed point “A”. The yield stress of the material is known to be 500 MPa. Answer the questions below Describe the stresses at point “A” and their causes and calculate the stresses. Determine the factor of safety against yield assuming the Tresca yield criteria. Determine the factor of safety against yield assuming the von Mises yield criteria using both principal stresses and “Cartesian” stresses. Do your values match or not, and is this expected? Explain. Do the calculated values make sense with the respect to the Tresca value? Explain, why or why not?arrow_forwardPROBLEM 4. The rigid bar is supported by a pin at A and two metal wires, each having a diameter of 4 mm. The stress-strain diagram of the steel is given in the Figure below. The lower graph is the zoomed view of the elastic deformation and yielding phases of the stress-strain diagram given by the upper graph (a) Obtain the Young's modulus of metal. What can you say about the kind of metal considering the Young modulus? If the point G is displaced 1.5 mm in vertical direction, (b) determine the forces at wires EB and DC, (b) the intensity of the distributed load w, (c) the final diameters of wires. (Poisson's ratio is v-0.3) E D o (MPa) 600 500 800 mm 400 300 G. 200 10 W 400 mm 250 mm- e(mm/mm) 150 mm 0.04 0.08 0.12 0.16 0.20 0.24 0.28 00005 00010.0015 Q002 00025 0,003 00035arrow_forward(Suppose you need to design a tension test machine capable of testing specimens that have nominal ultimate stresses as high as σu = 100 ksi . How much force must the machine be capable of generating? Assume the testing specimen has the ASTM shape shown. Answer for this is 19.6 kip) (If the maximum nominal strain is ϵf = 0.7 just before the test specimen fractures and the test machine operates by moving only one grip, how far must that grip be designed to travel? The total length of the deforming part of the specimen is 3 in. Answer for this is 2.10 in) Do not know if this info is needed but this was the other 2 partsarrow_forward
- A bar of 4340 steel has an Sy = 50 ksi. Which of these statements is true: If Sy = 50 ksi, than the normal stress in the bar is always 50 ksi. If a normal stress of 40 ksi is applied to the bar, it will undergo plastic deformation. The Sy = 50 ksi indicates bar is behaving in a brittle manner. O Any normal stress above 50 ksi will cause plastic deformation in the bar.arrow_forwardExample: Convert the change in length data in Table 3-2 to engineering stress and strain and plot a stress-strain curve Homework- help Table 3-2 The results of a tensile test of a 0.505 in. diameter aluminum alloy test bar, initial length (1o) = 2 in. Calculated LTO Load (Ib) Change in Length (in.) Stress (psi) Strain (in./in.) 0.000 1000 0.001 0.0005 4,993 14,978 24,963 34,948 37,445 39,442 39,941 39,691 37,944 3000 0.003 0.0015 5000 0.005 0.0025 7000 0.007 0.0035 7500 0.030 0.0150 7900 0.080 0.0400 8000 (maximum load) 0.120 0.0600 7950 0.160 0.0800 7600 (fracture) 0.205 0.1025arrow_forwardAfter explaining the difference between the true stress/strain and the nominal stress/strain, show the true stress-strain diagram for the nominal stress-strain diagram (Figure 1) to correspond points 1, 2, 3, and 4.arrow_forward
- 4. The maximum stress a human tendon can withstand is estimated to be 1200 MPa. If you were to test it for rupture what load cell you should use (25ON or 5kN) what problems may occur if you select an incorrect load cell. 5. The figure below is a J-shaped (or concave upward) stress-strain curve. What does a J-shaped stress stain curve indicate about a material's response to stress and tendency to yield? Name two materials that have J-shaped stress strain curves.arrow_forwardAssume the following elastic loading exists on ablock of copper:σX = 325 MPa; σY = 80 MPa; and τXY = 40 MPaCalculate eX and eZ for this block, assuminga. that it is a random polycrystalline material.b. that it is a single crystal with the tensile and shearaxes lining up along unit cell axes.c. Explain why the relative strain values you calculated along the X axis make sense for the two cases,based on the elastic anisotropy of copper.arrow_forwarda)Draw the stress-strain curve of a ductile material such as that of a ductile steel and discuss the various regions of the curve. Explain the difference between a ductile and brittle material and the concept of ductility and its measurement. b)A machine part 10 mm thick, having the dimensions shown in the figure, is to be subjected to cyclic loading. If the maximum stress is limited to 60 MPa, determine the allowable force P. Approximate the stress concentration factors form the graph given. Where might a potential fracture occur?arrow_forward
- A bar of a steel alloy that exhibits the stress–strain behavior shown in Animated Figure 7.34 is subjected to a tensile load; the specimen is 375 mm (14.8 in.) long and has a square cross section 5.5 mm (0.22 in.) on a side.(a) Compute the magnitude of the load necessary to produce an elongation of 7.5 mm (0.30 in.). _____________________________________________________ N (b) What will be the deformation after the load has been released? _______________________________________________________ mmarrow_forwardIn the picture there is a sketch of a socket wrench. Assume the wrench is held at a fixed point “A”. The yield stress of the material is known to be 400 MPa. Answer the questions below Describe the stresses at point “A” and their causes and calculate the stresses. Determine the factor of safety against yield assuming the Tresca yield criteria. Determine the factor of safety against yield assuming the von Mises yield criteria using both principal stresses and “Cartesian” stresses. Do your values match or not, and is this expected? Explain. Do the calculated values make sense with the respect to the Tresca value? Explain, why or why not?arrow_forwardDerive the following equation for computing shear stress in a solid bar along an oblique plane with angle B with respect to the vertical plane. The bar is subjected to centric axial loading. sin 0 cos 0 T = Aoarrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Elements Of ElectromagneticsMechanical EngineeringISBN:9780190698614Author:Sadiku, Matthew N. O.Publisher:Oxford University Press
Mechanics of Materials (10th Edition)Mechanical EngineeringISBN:9780134319650Author:Russell C. HibbelerPublisher:PEARSON
Thermodynamics: An Engineering ApproachMechanical EngineeringISBN:9781259822674Author:Yunus A. Cengel Dr., Michael A. BolesPublisher:McGraw-Hill Education
Control Systems EngineeringMechanical EngineeringISBN:9781118170519Author:Norman S. NisePublisher:WILEY
Mechanics of Materials (MindTap Course List)Mechanical EngineeringISBN:9781337093347Author:Barry J. Goodno, James M. GerePublisher:Cengage Learning
Engineering Mechanics: StaticsMechanical EngineeringISBN:9781118807330Author:James L. Meriam, L. G. Kraige, J. N. BoltonPublisher:WILEY
Elements Of Electromagnetics
Mechanical Engineering
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Oxford University Press
Mechanics of Materials (10th Edition)
Mechanical Engineering
ISBN:9780134319650
Author:Russell C. Hibbeler
Publisher:PEARSON
Thermodynamics: An Engineering Approach
Mechanical Engineering
ISBN:9781259822674
Author:Yunus A. Cengel Dr., Michael A. Boles
Publisher:McGraw-Hill Education
Control Systems Engineering
Mechanical Engineering
ISBN:9781118170519
Author:Norman S. Nise
Publisher:WILEY
Mechanics of Materials (MindTap Course List)
Mechanical Engineering
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Cengage Learning
Engineering Mechanics: Statics
Mechanical Engineering
ISBN:9781118807330
Author:James L. Meriam, L. G. Kraige, J. N. Bolton
Publisher:WILEY
Understanding Stress Transformation and Mohr's Circle; Author: The Efficient Engineer;https://www.youtube.com/watch?v=_DH3546mSCM;License: Standard youtube license