Biology: The Dynamic Science (MindTap Course List)
4th Edition
ISBN: 9781305389892
Author: Peter J. Russell, Paul E. Hertz, Beverly McMillan
Publisher: Cengage Learning
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Textbook Question
Chapter 13.3, Problem 1SB
What mechanisms are responsible for: (a) duplication of a chromosome segment; (b) generation of a Down syndrome individual; (c) a chromosome translocation; and (d) polyploidy?
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With detailed accounts of their various forms, explain any three of the following chromosomal aberrations:
a) Deletions
b) Duplications
c) Translocations
d)Inversion
A white-eyed (X-linked recessive character) female fruit fly is mated to a red-eyed male. One of their progeny is a white-eyed female. What is the most likely set of chromosomes of this whiteeyed daughter?
A) XXY B) XX C) XO D) XXX E) XYY
Which type(s) of chromosomal aberrations is/are likely to cause semisterility? Select all correct answers.
A.)reciprocal translocations
B.)deletions
C.)inversions
D.) duplications
Chapter 13 Solutions
Biology: The Dynamic Science (MindTap Course List)
Ch. 13.1 - You want to determine whether genes a and b are...Ch. 13.2 - You have a true-breeding strain of...Ch. 13.3 - What mechanisms are responsible for: (a)...Ch. 13.4 - A man has Simpson syndrome, an addiction to a...Ch. 13.4 - Prob. 2SBCh. 13.5 - Prob. 1SBCh. 13 - In humans, redgreen color blindness is an X-linked...Ch. 13 - The following pedigree shows the pattern of...Ch. 13 - Individuals affected by a condition known as...Ch. 13 - A number of genes carried on the same chromosome...
Ch. 13 - Prob. 5TYKCh. 13 - Discuss Concepts Can a linkage map be made for a...Ch. 13 - In Drosophila, two genes, one for body color and...Ch. 13 - Another gene in Drosophila determines wing length....Ch. 13 - Prob. 9TYKCh. 13 - You conduct a cross in Drosophila that produces...Ch. 13 - Discuss Concepts Crossing-over does not occur...Ch. 13 - Prob. 12TYKCh. 13 - Prob. 13TYKCh. 13 - Prob. 14TYKCh. 13 - Prob. 1ITDCh. 13 - Prob. 2ITDCh. 13 - Prob. 3ITDCh. 13 - Prob. 4ITD
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- Which of the following chromosomal events can result in Down’s Syndrome offspring? a) Primary nondisjunction of chromosome 21 b) Secondary nondisjunction of chromosome 21 c) A parent with a Robertsonian Translocation of 21 to 14 d) All of the abovearrow_forwardWhich of the following can NOT be determined through cytogenetics? A) polyploidy B) chromosome inversions C) single gene mutations D) aneuploidy E) translocationsarrow_forwardDuring meiotic prophase in a eukaryotic cell, Spo11 initiates recombination by causing a double-strand break in DNA between Gene A and Gene B on one sister chromatid. Which of these events will occur prior to formation of a Holliday junction? A) A heteroduplex forms due to pairing of Gene A and Gene B. B) Resolvase cuts all four chromatids. C) Spo11 causes a double-strand break in a nonsister chromatid. D) Strand invasion causes one strand of the uncut chromatid to form a D loop. E) Branch migration lengthens the heteroduplex region to include Gene A and Genearrow_forward
- A. Aneuploidy refers to the loss or gain a chromosome part. B. Polyploid cells have extra chromosome sets. A) Both statement is correct B) Both statement is incorrect C) First statement is correct, Second is incorrect D) First statement is incorrect, Second is correctarrow_forwardAn individual has a deletion of part of the short arm of chromosome 5. This individual also has a normal copy of chromosome 5. Would you expect this individual to have Cri-du-chat syndrome? Why or why not? Question 7 options: A) Yes, because they will inactivate their normal chromosome 5 B) Yes, because they only contain one copy of some of their genes C) No, because this is a terminal deficiency D) No, because they still have at least one copy of all the genes on chromosome 5arrow_forwardWhich sentence does not describe a way in which genetic variation increases during meiosis? A) Random segregation of homologous chromosomes during metaphase/anaphase I. B) Random mutation of the genetic code during DNA replication. C) Random segregation of chromatids during metaphase/anaphase II. D) Crossing-over of homologous chromosomes, to exchange parts of their arms. 2. Choose the correct word to describe the physical, biochemical and behavioural characteristics of an individual, caused by how their genes interact with the environment? A) Morphology B) Genotype C) Physiology D) Phenotype 3. 0000 A) 25 % B) 50% C) 75 % D) 100 % 0000 Two individuals who are heterozygous for gene Y have a child. What is the probability that their child will be heterozygous for the gene? 0000arrow_forward
- 19. Independent assortment of chromosomes is a result of which of the following processes? A) the random way each pair of homologous chromosomes lines up at the metaphase plate during meiosis I B) the random combinations of eggs and sperm during fertilization C) the random distribution of the sister chromatids to the two daughter cells during anaphase II D) the diverse combination of alleles that may be found within any given chromosome 20. Which of the following statements is correct in describing the terms monohybrid cross and dihybrid cross? A) A monohybrid cross involves a single parent, whereas a dihybrid cross involves two parents. B) A dihybrid cross involves organisms that are heterozygous for two traits that are being studied, and a monohybrid cross involves organisms that are heterozygous for only one trait being studied. C) A monohybrid cross is performed for one generation, whereas a dihybrid cross is performed for two generations. D) A monohybrid cross results in a 9:3:3:1…arrow_forwardThe karyotype of a young girl who is affected with Down syndrome revealed that she has 46 chromosomes. Her phenotypically normal older brother's karyotype revealed that he has 45 chromosomes. (a) Propose an explanantion for the chromosome number in both children (b) What would you expect the chromosome number of the parents of these two children?arrow_forwardIn a human karyotype, chromosomes are arranged in 23 pairs. If one of the autosomal pairs is examined, which of the following characteristics will the two chromosomes of the pair have in common? a) loci and staining pattern b) length and DNA sequence c) X-like shape and alignment on the metaphase plate d) alleles and centromere positionarrow_forward
- An error occurred during meiotic cell division, and a human egg has an extra copy of chromosome 21. That egg was fertilized by a normal sperm to create an embryo. This would lead to an individual A) who was tetraploid B) who would be normal in chromosomal number C) who had trisomy D) who was triploidarrow_forwardThe amount of crossing over is primarily determine by the a) length of the linked genes b) size of the linkage group c) size of the centromeres d) distance between the linked genes e) length of the chromosomearrow_forward1) What type of chromosome abnormality does the father have? a)Duplication b)Inversion c)Deletion d)Translocation 2) Why does the father have a normal phenotype? a) Because the translocation was reciprocal. b) Because he has one wild-type copy of each chromosome. c) Because the translocation occurred only in the father's gametes. d) Because no genes are missing.arrow_forward
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