Chapter 8.5, Problem 8.5CIAP

Interpretation Introduction

Interpretation:

The given pressure in $\text{mm}\text{Hg}$ should be expressed in $\text{in}\text{Hg}$ and it should be compared with ambient barometric pressure.

Concept introduction:

$\text{Pressure}\text{=}\frac{\text{Force}}{\text{Area}}$

Pressure can be expressed in different units. But it is normally reported in $\text{mm}\text{Hg}\left(\text{millimeters}\text{of}\text{mercury}\right)$

General unit conversions:

$\begin{array}{c}\text{1}\text{atm}\text{=}\text{760}\text{mm}\text{Hg}\text{=}\text{14}\text{.7}\text{psi}\text{=}\text{101,325}\text{Pa}\text{}\\ \text{760}\text{mm}\text{Hg}\text{=}29.92\text{inHg}\\ \text{1}\text{atm}\text{=}\text{760}\text{torr}\\ \text{1}\text{pascal}\text{=}\text{1}\text{newton}/{\text{meter}}^{\text{2}}\\ \text{1}\text{atm}\text{=}\text{760}\text{mm}\text{Hg}\text{=}\text{101}\text{.325}\text{kilopascals}\text{=}\text{1}\text{.01325}\text{bar}\\ \text{1}\text{bar}\text{=}{\text{1×10}}^{\text{5}}\text{pascal}\end{array}$