Shigley's Mechanical Engineering Design (McGraw-Hill Series in Mechanical Engineering)
10th Edition
ISBN: 9780073398204
Author: Richard G Budynas, Keith J Nisbett
Publisher: McGraw-Hill Education
expand_more
expand_more
format_list_bulleted
Textbook Question
Chapter 5, Problem 46P
5-39* to 5-55* For the problem specified in the table, build upon the results of the original problem to determine the minimum factor of safety for yielding. Use both the maximum-shear-stress theory and the distortion-energy theory, and compare the results. The material is 1018 CD steel.
Problem Number | Original Problem, Page Number |
5–39* | 3–68, 151 |
5–40* | 3–69, 151 |
5–41* | 3–70, 151 |
5–42* | 3–71, 151 |
5–43* | 3–72, 152 |
5–44* | 3–73, 152 |
5–45* | 3–74, 152 |
5–46* | 3–76, 153 |
5–47* | 3–77, 153 |
5–48* | 3–79, 153 |
5–49* | 3–80, 153 |
5–50* | 3–81, 154 |
5–51* | 3–82, 154 |
5–52* | 3–83, 154 |
5–53* | 3–84, 154 |
5–54* | 3–85, 155 |
5–55* | 3–86, 155 |
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
5-63
The figure shows a shaft mounted in bearings at A and D and having pulleys at B and C. The
forces shown acting on the pulley surfaces represent the belt tensions. The shaft is to be made of
AISI 1035 CD steel. Using a conservative failure theory with a design factor of 2, determine the
minimum shaft diameter to avoid yielding.
f-in R
300 Ibf
50 lbf
59 Ibf
392 lbf D
Problem 5-63
C 6 in
8-in D.
8 in
B
8 in
The plate of the figure is subjected to a bending moment with irregular cycles, which are
repeated. In the graphic one of this cycles is represented in terms of stress which appears in
each section whose height is h. The piece is made of ductile steel. Determine the number
of repetitions of the sequence which the piece can resist before the failure takes place due
to fatigue considering a reliability of 95 %.
Data: Sult = 1.000 MPa
Syp 3D800 Mра
thickness e = 4 mm
H = 10 cm
h = 5 cm
r=1 cm
ka = 0,72
kp = 0,95
S(MPa)
M
400
h
300
200
100
W
-100
-200
Refer to the figure below (from Example 5-3 on pp.259-260 in the
textbook). In addition to the load at point D, if another load Q
(Q=100F) along x direction acts at the right end of the 18-in bar, solve
for the maximum load F with a safety factor of 2.0 using distortion
energy theory. Find all the stress components at the origin point O.
Assume the yield strength of the steel is 42 kpsi with v=0.3.
2 in
12 in
글-in D.
-in R.
B
2 in
1-in D.
15 in
1-in D.
Chapter 5 Solutions
Shigley's Mechanical Engineering Design (McGraw-Hill Series in Mechanical Engineering)
Ch. 5 - A ductile hot-rolled steel bar has a minimum yield...Ch. 5 - A ductile hot-rolled steel bar has a minimum yield...Ch. 5 - A ductile hot-rolled steel bar has a minimum yield...Ch. 5 - A ductile hot-rolled steel bar has a minimum yield...Ch. 5 - A ductile hot-rolled steel bar has a minimum yield...Ch. 5 - Prob. 6PCh. 5 - 5-7 to 5-11 An AISI 1018 steel has a yield...Ch. 5 - 5-7 to 5-11 An AISI 1018 steel has a yield...Ch. 5 - 5-7 to 5-11 An AISI 1018 steel has a yield...Ch. 5 - 5-7 to 5-11 An AISI 1018 steel has a yield...
Ch. 5 - 5-7 to 5-11 An AISI 1018 steel has a yield...Ch. 5 - A ductile material has the properties Syt = 60...Ch. 5 - Prob. 13PCh. 5 - Prob. 14PCh. 5 - Prob. 15PCh. 5 - 5-14 to 5-18 An AISI 4142 steel QT at 800F...Ch. 5 - 5-14 to 5-18 An AISI 4142 steel QT at 800F...Ch. 5 - 5-14 to 5-18 An AISI 4142 steel QT at 800F...Ch. 5 - A brittle material has the properties Sut = 30...Ch. 5 - Repeat Prob. 519 by first plotting the failure...Ch. 5 - For an ASTM 30 cast iron, (a) find the factors of...Ch. 5 - For an ASTM 30 cast iron, (a) find the factors of...Ch. 5 - Prob. 23PCh. 5 - For an ASTM 30 cast iron, (a) find the factors of...Ch. 5 - 5-21 to 5-25 For an ASTM 30 cast iron, (a) find...Ch. 5 - 5-26 to 5-30 A cast aluminum 195-T6 exhibits Sut =...Ch. 5 - 5-26 to 5-30 A cast aluminum 195-T6 exhibits Sut =...Ch. 5 - 5-26 to 5-30 A cast aluminum 195-T6 exhibits Sut =...Ch. 5 - 5-26 to 5-30 A cast aluminum 195-T6 exhibits Sut =...Ch. 5 - 5-26 to 5-30 A cast aluminum 195-T6 exhibits Sut =...Ch. 5 - 5-31 to 5-35 Repeat Probs. 526 to 530 using the...Ch. 5 - 5-31 to 5-35 Repeat Probs. 526 to 530 using the...Ch. 5 - Repeat Probs. 526 to 530 using the modified-Mohr...Ch. 5 - Repeat Probs. 526 to 530 using the modified-Mohr...Ch. 5 - Repeat Probs. 526 to 530 using the modified-Mohr...Ch. 5 - This problem illustrates that the factor of safety...Ch. 5 - For the beam in Prob. 344, p. 147, determine the...Ch. 5 - A 1020 CD steel shaft is to transmit 20 hp while...Ch. 5 - For the problem specified in the table, build upon...Ch. 5 - For the problem specified in the table, build upon...Ch. 5 - 5-39 to 5-55 For the problem specified in the...Ch. 5 - Prob. 42PCh. 5 - For the problem specified in the table, build upon...Ch. 5 - For the problem specified in the table, build upon...Ch. 5 - Prob. 45PCh. 5 - 5-39 to 5-55 For the problem specified in the...Ch. 5 - Prob. 47PCh. 5 - For the problem specified in the table, build upon...Ch. 5 - For the problem specified in the table, build upon...Ch. 5 - For the problem specified in the table, build upon...Ch. 5 - For the problem specified in the table, build upon...Ch. 5 - 5-39 to 5-55 For the problem specified in the...Ch. 5 - 5-39 to 5-55 For the problem specified in the...Ch. 5 - For the problem specified in the table, build upon...Ch. 5 - For the problem specified in the table, build upon...Ch. 5 - Build upon the results of Probs. 384 and 387 to...Ch. 5 - Using F = 416 lbf, design the lever arm CD of Fig....Ch. 5 - A spherical pressure vessel is formed of 16-gauge...Ch. 5 - This problem illustrates that the strength of a...Ch. 5 - Prob. 60PCh. 5 - A cold-drawn AISI 1015 steel tube is 300 mm OD by...Ch. 5 - Prob. 62PCh. 5 - The figure shows a shaft mounted in bearings at A...Ch. 5 - By modern standards, the shaft design of Prob. 563...Ch. 5 - Build upon the results of Prob. 340, p. 146, to...Ch. 5 - For the clevis pin of Prob. 340, p. 146, redesign...Ch. 5 - A split-ring clamp-type shaft collar is shown in...Ch. 5 - Prob. 68PCh. 5 - Prob. 69PCh. 5 - Prob. 70PCh. 5 - Two steel tubes have the specifications: Inner...Ch. 5 - Repeal Prob. 5-71 for maximum shrink-fit...Ch. 5 - Prob. 73PCh. 5 - Two steel lubes are shrink-filled together where...Ch. 5 - Prob. 75PCh. 5 - Prob. 76PCh. 5 - Prob. 77PCh. 5 - Prob. 78PCh. 5 - Prob. 79PCh. 5 - Prob. 80PCh. 5 - Prob. 81PCh. 5 - For Eqs. (5-36) show that the principal stresses...Ch. 5 - Prob. 83PCh. 5 - A plate 100 mm wide, 200 mm long, and 12 mm thick...Ch. 5 - A cylinder subjected to internal pressure pi has...
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.Similar questions
- This problem illustrates that the factor of safety for a machine element depends on the particular point selected for analysis. Here you are to compute factors of safety, based upon the distortion-energy theory, for stress elements at A and B of the member shown in the figure. This bar is made of AISI 1006 cold-drawn steel and is loaded by the forces F = 0.55 kN, P = 8.0 kN, and T = 30 N m = 280 MPa 100 mm A B d=20 mmarrow_forwardConsider a machine element as shown in the figure. The stress element at a critical point on this element is shown. Determine the smallest yield stress for a steel that can be selected for the member, based on the maximum-shear-stress theory. What result you expect if maximum distortion energy theory is used. 80ksi 25 ksiarrow_forward6-10 A rotating shaft of 25-mm diameter is simply supported by bearing reaction forces R, and R2. The shaft is loaded with a transverse load of 13 kN as shown in the figure. The shaft is made from AISI 1045 hot-rolled steel. The surface has been machined. Determine (a) the minimum static factor of safety based on yielding. (b) the endurance limit, adjusted as necessary with Marin factors. (c) the minimum fatigue factor of safety based on achieving infinite life. (d) If the fatigue factor of safety is less than 1 (hint: it should be for this problem), then estimate the life of the part in number of rotations.arrow_forward
- This problem illustrates that the factor of safety for a machine element depends on the particular point selected for analysis. Here you are to compute factors of safety, based upon the distortion-energy theory, for stress elements at A and B of the member shown in the figure. This bar is made of AISI 1006 cold-drawn steel and is loaded by the forces F= 0.55 kN, P = 4 kN, and T = 25 N·m. Given: Sy= 280 MPa. NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. 15-mm D. -100 mm- T P Farrow_forwardRequired information This problem illustrates that the factor of safety for a machine element depends on the particular point selected for analysis. Here you are to compute factors of safety, based upon the distortion-energy theory, for stress elements at A and B of the member shown in the figure. This bar is made of AISI 1006 cold-drawn steel and is loaded by the forces F= 0.55 kN, P= 4 kN, and T=25 N-m. Given: Sy= 280 MPa. NOTE: This is a multi-part question. Once an answer is submitted, you will be unable to return to this part. B 15-mm D. -100 mm What is the value of the axial stress at point A? The value of the axial stress at point A is MPa.arrow_forwardCalculate the safety factors, based on the theory of distortion energy and maximum shear stress, for the hardest point in the embedment A or B of the element shown in the figure. This bar is made of hot rolled AISI 1006 steel and is subjected to the forces F = 0.40 kN, F2 = 0.20kN, P = 6.5 kN,T = 35N-m.arrow_forward
- 4. A bar of steel has minimum properties of Se= 40 kpsi, Sy = 60 kpsi, and Sut = 80 kpsi. The rotating bar is subjected to a steady torsional stress of 15 kpsi with a completely reversed bending stress of 25 kpsi. Find the factor of safety guarding against first-cycle yielding and either the factor of safety guarding against fatigue failure or the expected life of the part. For the fatigue analysis, use: 1) Goodman criterion 2) Gerber criterionarrow_forwardSolve the preceding problem if the thickness of the steel plate is. t = 12 mm. the gage readings are x = 530 × 10-6 (elongation) and y = -210 -× l0-6 (shortening), the modulus is E = 200 GPa, and Poisson’s ratio is v = 0.30.arrow_forwardA circular steel tube with an outer diameter of 75 mm and inner diameter of 65 mm is subjected to torques 7"at its ends. Calculate the maximum permissible torque 7jliajl if the allowable normal strain is ea= 5 X 10"4 Assume that G = 15 GPa.arrow_forward
- Two sections of steel drill pipe, joined by bolted flange plates at Ä are being tested to assess the adequacy of both the pipes. In the test, the pipe structure is fixed at A, a concentrated torque of 500 kN - m is applied at x = 0.5 m, and uniformly distributed torque intensity t1= 250 kN m/m is applied on pipe BC. Both pipes have the same inner diameter = 200 mm. Pipe AB has thickness tAB=15 mm, while pipe BC has thickness TBC= 12 mm. Find the maximum shear stress and maximum twist of the pipe and their locations along the pipe. Assume G = 75 GPa.arrow_forwardThree round, copper alloy bars having the same length L but different shapes are shown, in the figure. The first bar has a diameter d over its entire length, the second has a diameter d over one-fifth of its length, and the third has a diameter d over one-fifteenth of its length. Elsewhere, the second and third bars have a diameter Id. All three bars are subjected to the same axial load P. Use the following numerical data: P = 1400 kN, L = 5m,d= 80 mm, E= 110 GPa. and v = 0.33. (a) Find the change in length of each bar. (b) Find the change in volume of each bar.arrow_forwardA polyethylene tube (length L) has a cap that when installed compresses a spring (with under-formed length L1) by an amount ?? = (L1 = L). Ignore deformations of the cap and base. Use the force at the base of the spring as the redundant. Use numerical properties given in the boxes. (a) What is the resulting Force-in the spring, Fk? (b) What is the resulting Force in the tube, Ftl (c) What is the filial length of the tube, Lf? (d) What temperature change ?T inside the tube will result in zero force in the springarrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Mechanics of Materials (MindTap Course List)Mechanical EngineeringISBN:9781337093347Author:Barry J. Goodno, James M. GerePublisher:Cengage Learning
Mechanics of Materials (MindTap Course List)
Mechanical Engineering
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Cengage Learning
Understanding Failure Theories (Tresca, von Mises etc...); Author: The Efficient Engineer;https://www.youtube.com/watch?v=xkbQnBAOFEg;License: Standard youtube license