Shigley's Mechanical Engineering Design (McGraw-Hill Series in Mechanical Engineering)
10th Edition
ISBN: 9780073398204
Author: Richard G Budynas, Keith J Nisbett
Publisher: McGraw-Hill Education
expand_more
expand_more
format_list_bulleted
Concept explainers
Textbook Question
Chapter 5, Problem 56P
Build upon the results of Probs. 3–84 and 3–87 to compare the use of a low-strength, ductile material (1018 CD) in which the stress-concentration factor can be ignored to a high-strength but more brittle material (4140 Q&T @ 400°F) in which the stress-concentration factor should be included. For each case, determine the factor of safety for yielding using the distortion-energy theory.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
A pressure vessel is exposed to a combination of loads as shown below. The vessel (diameter 100 mm) has a wall
thickness of 3 mm. Address the following:
alf the yield strength of the material is 144 MPa, determine the largest tension force P with respect to a factor of
safety of 2 applied to the distortional energy theory.
appli
75 wit
and tension load were removed, determine
o the distortional energy theory. Illustrate yo
p = 3.5 MPa
T = 450 N-m
P
T
T
P
actor of safety
priate yield envelope.
2. Consider a bar of AISI 1015 cold-drawn steel. Using the distortion-energy and
maximum-shear-stress theories to determine the factors of safety for a stress state
with the following plane principal stresses: 04 = 30 kpsi, OB = 15 kpsi.
The bxd xhrubber blocks shown are used in a double U shear mount to isolate the vibration of a machine from its supports. An
applied load of P- 750 N causes the upper frame to be deflected downward by 4.9 mm. Determine the average shear strain and the
shear stress in the rubber blocks. Assume b 16 mm, d 28 mm, and h= 28.
Double U
anti-vibration
shear mount
Rubber block
dimensions
Shear deformation
of blocks
Answers:
Average shear strain-
rad.
Average shear stress-
kPa.
478316
Chapter 5 Solutions
Shigley's Mechanical Engineering Design (McGraw-Hill Series in Mechanical Engineering)
Ch. 5 - A ductile hot-rolled steel bar has a minimum yield...Ch. 5 - A ductile hot-rolled steel bar has a minimum yield...Ch. 5 - A ductile hot-rolled steel bar has a minimum yield...Ch. 5 - A ductile hot-rolled steel bar has a minimum yield...Ch. 5 - A ductile hot-rolled steel bar has a minimum yield...Ch. 5 - Prob. 6PCh. 5 - 5-7 to 5-11 An AISI 1018 steel has a yield...Ch. 5 - 5-7 to 5-11 An AISI 1018 steel has a yield...Ch. 5 - 5-7 to 5-11 An AISI 1018 steel has a yield...Ch. 5 - 5-7 to 5-11 An AISI 1018 steel has a yield...
Ch. 5 - 5-7 to 5-11 An AISI 1018 steel has a yield...Ch. 5 - A ductile material has the properties Syt = 60...Ch. 5 - Prob. 13PCh. 5 - Prob. 14PCh. 5 - Prob. 15PCh. 5 - 5-14 to 5-18 An AISI 4142 steel QT at 800F...Ch. 5 - 5-14 to 5-18 An AISI 4142 steel QT at 800F...Ch. 5 - 5-14 to 5-18 An AISI 4142 steel QT at 800F...Ch. 5 - A brittle material has the properties Sut = 30...Ch. 5 - Repeat Prob. 519 by first plotting the failure...Ch. 5 - For an ASTM 30 cast iron, (a) find the factors of...Ch. 5 - For an ASTM 30 cast iron, (a) find the factors of...Ch. 5 - Prob. 23PCh. 5 - For an ASTM 30 cast iron, (a) find the factors of...Ch. 5 - 5-21 to 5-25 For an ASTM 30 cast iron, (a) find...Ch. 5 - 5-26 to 5-30 A cast aluminum 195-T6 exhibits Sut =...Ch. 5 - 5-26 to 5-30 A cast aluminum 195-T6 exhibits Sut =...Ch. 5 - 5-26 to 5-30 A cast aluminum 195-T6 exhibits Sut =...Ch. 5 - 5-26 to 5-30 A cast aluminum 195-T6 exhibits Sut =...Ch. 5 - 5-26 to 5-30 A cast aluminum 195-T6 exhibits Sut =...Ch. 5 - 5-31 to 5-35 Repeat Probs. 526 to 530 using the...Ch. 5 - 5-31 to 5-35 Repeat Probs. 526 to 530 using the...Ch. 5 - Repeat Probs. 526 to 530 using the modified-Mohr...Ch. 5 - Repeat Probs. 526 to 530 using the modified-Mohr...Ch. 5 - Repeat Probs. 526 to 530 using the modified-Mohr...Ch. 5 - This problem illustrates that the factor of safety...Ch. 5 - For the beam in Prob. 344, p. 147, determine the...Ch. 5 - A 1020 CD steel shaft is to transmit 20 hp while...Ch. 5 - For the problem specified in the table, build upon...Ch. 5 - For the problem specified in the table, build upon...Ch. 5 - 5-39 to 5-55 For the problem specified in the...Ch. 5 - Prob. 42PCh. 5 - For the problem specified in the table, build upon...Ch. 5 - For the problem specified in the table, build upon...Ch. 5 - Prob. 45PCh. 5 - 5-39 to 5-55 For the problem specified in the...Ch. 5 - Prob. 47PCh. 5 - For the problem specified in the table, build upon...Ch. 5 - For the problem specified in the table, build upon...Ch. 5 - For the problem specified in the table, build upon...Ch. 5 - For the problem specified in the table, build upon...Ch. 5 - 5-39 to 5-55 For the problem specified in the...Ch. 5 - 5-39 to 5-55 For the problem specified in the...Ch. 5 - For the problem specified in the table, build upon...Ch. 5 - For the problem specified in the table, build upon...Ch. 5 - Build upon the results of Probs. 384 and 387 to...Ch. 5 - Using F = 416 lbf, design the lever arm CD of Fig....Ch. 5 - A spherical pressure vessel is formed of 16-gauge...Ch. 5 - This problem illustrates that the strength of a...Ch. 5 - Prob. 60PCh. 5 - A cold-drawn AISI 1015 steel tube is 300 mm OD by...Ch. 5 - Prob. 62PCh. 5 - The figure shows a shaft mounted in bearings at A...Ch. 5 - By modern standards, the shaft design of Prob. 563...Ch. 5 - Build upon the results of Prob. 340, p. 146, to...Ch. 5 - For the clevis pin of Prob. 340, p. 146, redesign...Ch. 5 - A split-ring clamp-type shaft collar is shown in...Ch. 5 - Prob. 68PCh. 5 - Prob. 69PCh. 5 - Prob. 70PCh. 5 - Two steel tubes have the specifications: Inner...Ch. 5 - Repeal Prob. 5-71 for maximum shrink-fit...Ch. 5 - Prob. 73PCh. 5 - Two steel lubes are shrink-filled together where...Ch. 5 - Prob. 75PCh. 5 - Prob. 76PCh. 5 - Prob. 77PCh. 5 - Prob. 78PCh. 5 - Prob. 79PCh. 5 - Prob. 80PCh. 5 - Prob. 81PCh. 5 - For Eqs. (5-36) show that the principal stresses...Ch. 5 - Prob. 83PCh. 5 - A plate 100 mm wide, 200 mm long, and 12 mm thick...Ch. 5 - A cylinder subjected to internal pressure pi has...
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.Similar questions
- A propeller shaft for a small yacht is made of a solid steel bar 104 mm in diameter. The allowable stress in shear is 48 MPa, and the allowable rate of twist is 2.0° in 3.5 meters. (a) Assuming that the shear modulus of elasticity is G = 80 GPa, determine the maximum torque that can be applied to the shaft. (b) Repeat part (a) if the shaft is now hollow with an inner diameter of 5d18. Compare values to corresponding values from part (a).arrow_forwardThe strength-to-weight ratio of a structural material is defined as its load-carrying capacity divided by its weight. For materials in tension, use a characteristic tensile stress obtained from a stress-strain curve as a measure of strength. For instance, either the yield stress or the ultimate stress could be used, depending upon the particular application. Thus, the strength-to-weight ratio RS/Wfor a material in tension is defined as Rs/w= in which a is the characteristic stress and 7 is the weight density. Note that the ratio has units of length. Using the ultimate stress Uas the strength parameter, calculate the strength-to-weight ratio (in units of meters) for each of the following materials: aluminum alloy 606I-T6, Douglas fir (in bending}, nylon. structural steel ASTM-A57.2, and a titanium alloy. Obtain the material properties from Tables [-1 and 1-3 of Appendix I. When a range of values is given in a table, use the average value.arrow_forwardA pressure vessel is exposed to a combination of loads as shown below. The vessel (diameter 100 mm) has a wall thickness of 3 mm. Address the following: (a) If the yield strength of the material is 144 MPa, determine the largest tension force P with respect to a factor of safety of 2 applied to the distortional energy theory. (b) If the applied torque and tension load were removed, determine the minimum wall thickness using a factor of safety of 1.75 with respect to the distortional energy theory. Illustrate you results using an appropriate yield envelope. p = 3.5 MPa T = 450 N-m show all wah Parrow_forward
- 1. A ductile hot-rolled steel bar has a yield strength in tension and compression of 350 MPa. Using the distortion-energy and maximum-shear-stress theories, determine the factors of safety for the following plane stress state: 75 MPa 50 MPa 50 MPa 2. Consider a bar of AISI 1015 cold-drawn steel. Using the distortion-energy and maximum-shear-stress theories to determine the factors of safety for a stress state with the following plane principal stresses: 0A = 30 kpsi, OB = 15 kpsi.arrow_forwardProblem 1·16 At a point in a structural member subjected to plane stress, the state of stress is : 0x =70 MPa, ơ, MPa. Determine which of the theories of failure will predict failure by yielding for this state of stress if the yield strength of the material in tension and compression is 250 MPa. 56 MPa, txy -28arrow_forwardA pressure vessel is exposed to a combination of loads as shown below. The vessel (diameter 100 mm) has a wall thickness of 3 mm. Address the following: (a) If the yield strength of the material is 144 MPa, determine the largest tension force P with respect to a factor of safety of 2 applied to the distortional energy theory. (b) If the applied torque and tension load were removed, determine the minimum wall thickness using a factor of safety of 1.75 with respect to the distortional energy theory. Illustrate you results using an appropriate yield envelope. p = 3.5 MPa T = 450 N-m P Tarrow_forward
- The stresses on the surface of a ductile alloy component 50 MPa are as pictured. The yield strength of the alloy is oy = 190MPA. 100 MPa Find Principal Stresses: Отах MPa Omin MPа 50 MPa Calculate Mises equivalent stress for the given state of plane stress: OM MPa Calculate Factor of Safety predicted by the maximum-distortion-energy theory using Mises stress: FS Does the component fail according to this theory? Yes or No Calculate Factor of Safety predicted by the maximum-shear-stress theory of failure: FS Does the component fail according to this theory? Yes or Noarrow_forwardA mild steel shaft of 40 mm diameter is subjected to a bending moment of 115 N-m and torque, T. If the yield point of the steel in tension is 300 MPa, find the maximum value of torque T without causing yielding of the shaft according to von-Mises and Tresca failure theories.arrow_forwardA loading condition is shown below. The wires at point A and D both made from a steel with the yield strength (Sy) of 190 MPa with 2 mm diameter. Using either maximum shear stress theory or distortion energy theory, determine the maximum load P that can be applied before yielding happens in the wires.arrow_forward
- 2. The following handle is loaded at points B and C, as shown below. 0.8 m 40 mm 0.4 m If the force P = 20F, and the material of the handle has Sy = 250 MPa: a. Show the stress state at element A. b. Using the distortion energy theory, find the maximum force F that guarantees a safety factor of 1.4.arrow_forwardThe 0.06R (mm)-diameter bar is made of a brittle material with the ultimate strengths of 0.15R MPa in tension and 0.25R MPa in compression. The bar carries a bending moment and a torque, both of magnitude M. (a) Use the maximum normal stress theory to find the largest value of M that does not cause rupture. (b) Is the value of M found in Part (a) safe according to Mohr’s theory of failure? Note R=993arrow_forward5 The Mohr's circle of plane stress for a point in a body is shown. The design is to be done on the basis of the maximum shear stress theory for yielding. Then, yielding will just begin if the designer chooses a ductile material whose yield strength is t(MPa) o(MPa) -100 -10 (a) 45 MPa (c) 90 MPa (b) 50MPA (d) 100 MPaarrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Mechanics of Materials (MindTap Course List)Mechanical EngineeringISBN:9781337093347Author:Barry J. Goodno, James M. GerePublisher:Cengage Learning
Mechanics of Materials (MindTap Course List)
Mechanical Engineering
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Cengage Learning
Everything About COMBINED LOADING in 10 Minutes! Mechanics of Materials; Author: Less Boring Lectures;https://www.youtube.com/watch?v=N-PlI900hSg;License: Standard youtube license