Biochemistry: The Molecular Basis of Life
6th Edition
ISBN: 9780190209896
Author: Trudy McKee, James R. McKee
Publisher: Oxford University Press
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Chapter 6, Problem 21RQ
Summary Introduction
To review:
Features of the enzyme that are responsible for reducing the
Introduction:
The protein molecules that are involved in catalyzing biological reactions are called enzymes. A few molecules of ribonucleic acid (RNA), such as ribozymes, may also act as enzymes, but most of them are proteins. Enzyme activities are important as they can speed up the biological reactions manifold.
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Chapter 6 Solutions
Biochemistry: The Molecular Basis of Life
Ch. 6 - Prob. 1QCh. 6 - Prob. 2QCh. 6 - Prob. 3QCh. 6 - Prob. 4QCh. 6 - Prob. 5QCh. 6 - Prob. 6QCh. 6 - Prob. 7QCh. 6 - Prob. 8QCh. 6 - Prob. 9QCh. 6 - Prob. 1RQ
Ch. 6 - Prob. 2RQCh. 6 - Prob. 3RQCh. 6 - Prob. 4RQCh. 6 - Prob. 5RQCh. 6 - Prob. 6RQCh. 6 - Prob. 7RQCh. 6 - Prob. 8RQCh. 6 - Prob. 9RQCh. 6 - Prob. 10RQCh. 6 - Prob. 11RQCh. 6 - Prob. 12RQCh. 6 - Prob. 13RQCh. 6 - Prob. 14RQCh. 6 - Prob. 15RQCh. 6 - Prob. 16RQCh. 6 - Prob. 17RQCh. 6 - Prob. 18RQCh. 6 - Prob. 19RQCh. 6 - Prob. 20RQCh. 6 - Prob. 21RQCh. 6 - Prob. 22RQCh. 6 - Prob. 23RQCh. 6 - Prob. 24RQCh. 6 - Prob. 25RQCh. 6 - Prob. 26RQCh. 6 - Prob. 27RQCh. 6 - Prob. 28RQCh. 6 - Prob. 29RQCh. 6 - Prob. 30RQCh. 6 - Prob. 31RQCh. 6 - Prob. 32RQCh. 6 - Prob. 33RQCh. 6 - Prob. 34RQCh. 6 - Prob. 35RQCh. 6 - Prob. 36RQCh. 6 - Prob. 37RQCh. 6 - Prob. 38RQCh. 6 - Prob. 39RQCh. 6 - Prob. 40RQCh. 6 - Prob. 41RQCh. 6 - Prob. 42RQCh. 6 - Prob. 43FBCh. 6 - Prob. 44FBCh. 6 - Prob. 45FBCh. 6 - Prob. 46FBCh. 6 - Prob. 47FBCh. 6 - Prob. 48FBCh. 6 - Prob. 49FBCh. 6 - Prob. 50FBCh. 6 - Prob. 51FBCh. 6 - Prob. 52FBCh. 6 - Prob. 53SACh. 6 - Prob. 54SACh. 6 - Prob. 55SACh. 6 - Prob. 56SACh. 6 - Prob. 57SACh. 6 - Prob. 58TQCh. 6 - Prob. 59TQCh. 6 - Prob. 60TQCh. 6 - Prob. 61TQCh. 6 - Prob. 62TQCh. 6 - Prob. 63TQCh. 6 - Prob. 64TQCh. 6 - Prob. 65TQCh. 6 - Prob. 66TQCh. 6 - Prob. 67TQCh. 6 - Prob. 68TQCh. 6 - Prob. 69TQCh. 6 - Prob. 70TQCh. 6 - Prob. 71TQCh. 6 - Prob. 72TQCh. 6 - Prob. 73TQCh. 6 - Prob. 74TQCh. 6 - Prob. 75TQCh. 6 - Prob. 76TQCh. 6 - Prob. 77TQCh. 6 - Prob. 78TQCh. 6 - Prob. 79TQCh. 6 - Prob. 80TQCh. 6 - Prob. 81TQ
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- Table 1 shows the kinetic data that have been obtained for glucoamylase from Aspergillus niger at different temperatures in the production of glucose from maltodextrin. The rates of reaction measured are using an enzymes concentration of 0.003 μmolml-1. Outline and describe the reaction scheme of the production of glucose from maltodextrin by using glucoamylase.arrow_forwardIn enzyme kinetics, for the reversible with one complex mechanism, please provide complete proof that the rate equation is the equation below. The variables denoted with f indicates forward direction while the variables denoted with b indicate backward direction.arrow_forwardPyridoxal phosphate (PLP) is a coenzyme for the enzyme ornithine aminotransferase. The enzyme was purified from cells grow in PLP = deficient media as well as from cells grown in media that contained pyridoxal phosphate. The stability of the two different enzyme preparations was then measured by incubating the enzyme at 37°C for different lengths of time and then assaying for the amount of enzyme activity remaining. The following results were obtained. (a) Why does the amount of active enzyme decrease with the time of incubation? (b) Why does the amount of enzyme from the PLP deficient cells decline more rapidly?arrow_forward
- The Lineweaver-Burk plot, which illustrates the reciprocal of the reaction rate (1/v) versus the reciprocal of the substrate concentration (1/[S]), is a graphical representation of enzyme kinetics. This plot is typically used to determine the maximum rate, Vmax, and the Michaelis constant, Km, which can be gleaned from the intercepts and slope. Identify each intercept and the slope in terms of the constants Vmax and Km. What term is represented by C? Linewegver-Burk Pt 1/Vmax O A. В. -1/Km Km/Vmax C.arrow_forwardIdris has successfully extracted enzymatic proteins from the fish viscera (intestines and stomach). After homogenization and centrifugation, he managed to pool the crude enzyme extract. He is characterizing the enzymes. Please help Idris by answering the followingquestions: The enzyme has optimum activities at 35oC. With the correct captions for X and Y axes, help me to draw:(a). A temperature profile graph, from 20 to 70oC.(b). Please explain the two ways how temperature can affect the enzymereaction.arrow_forwardIdris has successfully extracted enzymatic proteins from the fish viscera (intestines and stomach). After homogenization and centrifugation, he managed to pool the crude enzyme extract. He is characterizing the enzymes. Please help Idris by answering the followingquestions:(a). How do I determine the enzyme activity? Please give the unit. (b) How do I get the specific activity of this enzyme? Please give the unit.arrow_forward
- One way of expressing the rate at which an enzyme can catalyze a reaction is to state its turnover number. The turnover number is the maximum number of substrate molecules that can be acted on by one molecule of enzyme per unit of time. The table gives the turnover number of four representative enzymes. Enzyme Substrate Turnover number (per second) Ribonuclease RNA 100 Fumarase fumarate 800 Lactate dehydrogenase lactate 1000 Urease urea 10,000 How many molecules of urea can one molecule of urease act on in 12.0 min ?arrow_forwardIn enzyme catalysed reactions, the energy level of the enzyme/substrate (or ES) complex is higher (or raised) compared to the uncatalyzed reaction. List 4 factors that contribute to this raised energy level and explain how each of these factors contribute to the higher energy level of the ES complexarrow_forwardCompounds I, II, and III are in the following biochemical pathway: precursor compound I enzyme A enzyme B compound II ► compound III enzyme Mutation a inactivates enzyme A, mutation b inactivates enzyme B, and mutation c inactivates enzyme C. Mutants, each having one of these defects, were tested on minimal medium to which compound I, II, or III was added. Fill in the results expected of these tests by placing a plus sign (+) for growth or a minus sign (-) for no growth in the table below. Minimal medium to which is added Strain with mutation Compound I Compound II Compound IIIarrow_forward
- There is a cysteine protease, which uses a similar chemical mechanism to chymotrypsin except for using cysteine instead of serine during catalysis. Please draw the stepwise chemical mechanism for the cysteine protease.arrow_forwardPenicillin is hydrolyzed and thereby rendered inactive by penicillinase, an enzyme present in some resistant bacteria. The mass of this enzyme in Staphylococcus aureus is 29.6 kd. The amount of penicillin hydrolyzed in 1 minute in 10 ml solution containing 10–9 g of purified penicillinase was measured as a function of the concentration of penicillin. Assume that the concentration of penicillin does not change during the assay. [Penicillin] µM Amount hydrolyzed (nanomoles) 1 0.11 3 0.25 5 0.34 10 0.45 30 0.58 50 0.61 a) Plot V0 versus [S] and 1/V0 1/[S]. Does penicillinase appear to obey Michaelis-Menten kinetics? b) What is the value of KM? c) What is the value of Vmax? d) What is the turnover number of penicillinase under these conditions?arrow_forwardUrease enzyme hydrolysed urea at [S]= 0.03 mmol/L with a Km value of around 0.06 mmol/L. The initial velocity observed was 1.5x103 mmol/L.min1. Calculate the initial velocity of the enzymatic reaction when using [S]= 0.12 mmol/L.arrow_forward
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