Concept explainers
(a)
To determine: The stability of the isomers of the given compound and the amount of energy that makes one of them stable.
Interpretation: The stability of the isomers of the given compound is to be determined and the amount of energy that makes one of them stable is to be calculated.
Concept introduction: The stability of
Heat of hydrogenation of an alkene is the standard enthalpy for the catalytic hydrogenation of the alkene. The value of heat of hydrogenation is always negative.
(b)
To determine: The stability of the given compound and the amount of energy that makes one of them stable.
Interpretation: The stability of the given compound is to be determined and the amount of energy that makes one of them stable is to be calculated.
Concept introduction: The stability of alkenes depends on the structure of alkene. The energy of alkene is measured by their heat of hydrogenation. More the heat of hydrogenation, more stable is the alkene.
Heat of hydrogenation of an alkene is the standard enthalpy for the catalytic hydrogenation of the alkene. The value of heat of hydrogenation is always negative.
(c)
To determine: The stability of the given compounds and the amount of energy that makes one of them stable.
Interpretation: The stability of the given compound is to be determined and the amount of energy that makes one of them stable is to be calculated.
Concept introduction: The stability of alkenes depends on the structure of alkene. The energy of alkene is measured by its heat of hydrogenation. More the heat of hydrogenation, more stable is the alkene.
Heat of hydrogenation of an alkene is the standard enthalpy for the catalytic hydrogenation of the alkene. The value of heat of hydrogenation is always negative.
(d)
To determine: The stability of the isomers of the given compound and the amount of energy that makes one of them stable.
Interpretation: The stability of the isomers of the given compound is to be determined and the amount of energy that makes one of them stable is to be calculated.
Concept introduction: The stability of alkenes is depends on the structure of alkene. The energy of alkene is measured by its heat of hydrogenation. More the heat of hydrogenation, more stable is the alkene.
Heat of hydrogenation of an alkene is the standard enthalpy for the catalytic hydrogenation of the alkene. The value of heat of hydrogenation is always negative.
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Organic Chemistry (9th Edition)
- H3C- -Br + а. b. H3C CH3 2 CH3CH,NH2arrow_forwardChoose the structure that fits the descriptions below from the pool of choices. Use the dropdown list to select your answers. RAT x HAT PAT VAT 1. A conjugated diene. [Select] 2. An isolated diene. [Select] a CAT MAT 3. An alkene with possible rearrangement product (1,2-H shift) with reaction to Hl. [Select] 4. A diene capable of having 1,2 and 1,4-addition products. [Select]arrow_forwardh. 3-methyl-1-butene with Hg(OAC)2 and CH3OH, followed later by NaBH4 CH3 H2C=CH-CH-CH3 Major Product(s) of h. Stereochemistry of the product described in h. (Circle one) а. R b. S С. Е d. Z e. a mixture of E and Z f. erythro g. threo h. a racemic (50/50) mixture i. all 4 products (a set of erythro and a set of threo) j. no stereochemistryarrow_forward
- for this question. Draw a structural formula for the missing product in the following reaction. 0. NaHCO3 H20 ? + CO2 + H20 + CH3C-OH • You do not have to consider stereochemistry. • You do not have to explicitly draw H atoms. • Include cationic counter-ions, e.g., Na+ in your answer, but draw them in their own sketcher. C P. opy aste [F **** C - Visited CH4 ChemDoodle Retry Entire Group 5 more group attempts remaining Submit Answerarrow_forwardI. Identify the compounds (reactants or products) corresponding to each letter. If there are several products possible, please put ONLY the major product. CH3 1 mole Br, 5. Hc F (Show stereochemistry of product) 6. CH;CH:C=CCH2CH3 + H;O (with H;S0, as catalyst)→ E (Show the stable structure)arrow_forwardto form the product shown. Diene + Dienophile -> ● al CH3O CN CN . Consider E/Z stereochemistry of alkenes. • Draw one structure per sketcher. Add additional sketchers using the drop-down menu in the bottom right corner. Separate multiple products using the + sign from the drop-down menu. ?arrow_forward
- Predict the major products. C,H5-C-CH; а. 1/2 b. (CH;),CH-C-Ħ#", heat (CH),СH-C-Нт C,H5-CH2-C-Ħ с. d. C,Hs-C-CH; H" CaH-C-CH С,Н-С-СH е. f. CHs-C-CH;¬N#OH CH;-C= C-CHOTE gSO g. h. C,Hs-C-C,H5 H*arrow_forwardDraw the products of the following reactions. If the products can exist as stereoisomers show what stereoisomers are formed. a. cis-2-pentene + Br2/CH2Cl2 b. trans-2-pentene + Br2/CH2Cl2 c. 1- butene + HCl d. methylcyclohexene + HBr e. trans-3-hexene + Br2/CH2Cl2 f. cis-3-hexene + Br2/CH2Cl2 g. 3,3-dimethyl-1-pentene + HBr h. cis-2-butene + HBr i. (Z)-2,3-dichloro-2-butene + H2, Pd/C j. (E)-2,3-dichloro-2-butene + H2, Pd/C k. (Z)-3,4-dimethyl-3-hexene + H2, Pd/C l. (E)-3,4-dimethyl-3-hexene + H2, Pd/Carrow_forwardGive the structure corresponding to each name. a. (E)-4-ethylhept-3-ene b.3,3-dimethylcyclopentene c.4-vinylcyclopentene d.(Z)-3-isopropylhept-2-ene e.cls-3,4-dimethylcyclopentene f.1-isopropyl-4-propylcyclohexene g.3,4-dimethylcyclohex-2-enol h.3,5-diethylhex-5-en-3-olarrow_forward
- 6. The Newman projection and an equivalent 3D projection for an alkyl bromide is shown below. Under E2 conditions, there is only one major alkene product. Ph H3C H H3C. H H Br CH₂CH3 = Ph. H Br E2 conditions major product a. In 1-2 sentences, explain why only one constitutional isomer (regioisomer) forms. b. Explain why only one stereoisomer is possible for this E2 reaction. In your explanation, draw the conformation of the alkyl bromide that reacts to form product.arrow_forwardg. cis-3-methylpent-2-ene with BH3, H2O2, and OH CH3 H3C- CH =C -CH2-CH3 Major Product(s) of g. Stereochemistry of the product described in g. (Circle one) а. R b. S С. Е d. Z e. a mixture of E and Z f. erythro g. threo h. a racemic (50/50) mixture i. all 4 products (a set of erythro and a set of threo) j. no stereochemistryarrow_forwardmethod 1 is better than Determine why is methed 2 s teos gpooduce CH. CH. - Method 1:- Hg (OAC} CH3-CH CH3 - CH3 NuBHy c-CH3 CH2=CH - c CH3 - Methad 2: C Hz=CH-ċ- CHz CHz-CH-Ċ-CH OH CH3 CH. artangement Re C3 CH3 CH3- CH-C-CH3 OHarrow_forward
- Organic Chemistry: A Guided InquiryChemistryISBN:9780618974122Author:Andrei StraumanisPublisher:Cengage Learning