Physics for Scientists and Engineers
6th Edition
ISBN: 9781429281843
Author: Tipler
Publisher: MAC HIGHER
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Chapter 36, Problem 22P
To determine
The proof that
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Check out a sample textbook solutionStudents have asked these similar questions
If, in
1
1
= Ry
-
you set ni = 1 and take n2 greater than 1,
you generate what is known as the Lyman
%3D
series.
Find the wavelength of the first mem-
ber of this series.
The value of ħ is
1.05457 × 10¬34 J.s; the Rydberg constant
for hydrogen is 1.09735 × 10’ m¬'; the Bohr
radius is 5.29177 × 10¬1" m; and the ground
state energy for hydrogen is 13.6057 eV.
Answer in units of nm.
Consider the next three members of this se-
ries. The wavelengths of successive members
of the Lyman series approach a common limit
as n2 → ∞.
What is this limit?
Answer in units of nm.
Assuming that only a single electron is present and a Bohr model, calculate the mean radius, orbital velocity, and energy of a
N=1 electron of hydrogen
N=4 electron for lead
N=1 electron for plutonium
N=1 electron for an element with Z = 142
The gravitational attraction between electron and proton in a hydrogen atom is weaker than the coulomb attraction by a factor of about 10-40. An alternative way of looking at this fact is to estimate the radius of the first Bohr orbit of a hydrogen atom if the electron and proton were bound by gravitational attraction. You will find the answer interesting.
Chapter 36 Solutions
Physics for Scientists and Engineers
Ch. 36 - Prob. 1PCh. 36 - Prob. 2PCh. 36 - Prob. 3PCh. 36 - Prob. 4PCh. 36 - Prob. 5PCh. 36 - Prob. 6PCh. 36 - Prob. 7PCh. 36 - Prob. 8PCh. 36 - Prob. 9PCh. 36 - Prob. 10P
Ch. 36 - Prob. 11PCh. 36 - Prob. 12PCh. 36 - Prob. 13PCh. 36 - Prob. 14PCh. 36 - Prob. 15PCh. 36 - Prob. 16PCh. 36 - Prob. 17PCh. 36 - Prob. 18PCh. 36 - Prob. 19PCh. 36 - Prob. 20PCh. 36 - Prob. 21PCh. 36 - Prob. 22PCh. 36 - Prob. 23PCh. 36 - Prob. 24PCh. 36 - Prob. 25PCh. 36 - Prob. 26PCh. 36 - Prob. 27PCh. 36 - Prob. 28PCh. 36 - Prob. 29PCh. 36 - Prob. 30PCh. 36 - Prob. 31PCh. 36 - Prob. 32PCh. 36 - Prob. 33PCh. 36 - Prob. 34PCh. 36 - Prob. 35PCh. 36 - Prob. 36PCh. 36 - Prob. 37PCh. 36 - Prob. 38PCh. 36 - Prob. 39PCh. 36 - Prob. 40PCh. 36 - Prob. 41PCh. 36 - Prob. 42PCh. 36 - Prob. 43PCh. 36 - Prob. 44PCh. 36 - Prob. 45PCh. 36 - Prob. 46PCh. 36 - Prob. 47PCh. 36 - Prob. 48PCh. 36 - Prob. 49PCh. 36 - Prob. 50PCh. 36 - Prob. 51PCh. 36 - Prob. 52PCh. 36 - Prob. 53PCh. 36 - Prob. 54PCh. 36 - Prob. 55PCh. 36 - Prob. 56PCh. 36 - Prob. 57PCh. 36 - Prob. 58PCh. 36 - Prob. 59PCh. 36 - Prob. 60PCh. 36 - Prob. 61PCh. 36 - Prob. 62PCh. 36 - Prob. 63PCh. 36 - Prob. 64PCh. 36 - Prob. 65PCh. 36 - Prob. 66PCh. 36 - Prob. 67PCh. 36 - Prob. 68PCh. 36 - Prob. 69PCh. 36 - Prob. 70PCh. 36 - Prob. 71PCh. 36 - Prob. 72PCh. 36 - Prob. 73PCh. 36 - Prob. 74PCh. 36 - Prob. 75P
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- If an atom has an election in the n = 5 state with m = 3, what are the possible values of l?arrow_forward(a) Using the Pauli exclusion principle and the rules relating the allowed values of the quantum numbers (n,l,ml,ms), prove that the maximum number of electrons in a subshell is 2n2. (b) In a similar manner, prove that the maximum number of electrons in a shell is 2n2.arrow_forwardAssume that in the Stem-Gerlach experiment as described for neutral silver atoms,the magnetic field B has a magnitude of 0.25 T. Calculate the energy difference between the magnetic moment orientations of the silver atoms in the two sub beams? a)111.97 Ghz b)83.98 Ghz c)7.00 Ghz d)20.99 Ghz e)41.99 Ghzarrow_forward
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