Physics for Scientists and Engineers
Physics for Scientists and Engineers
6th Edition
ISBN: 9781429281843
Author: Tipler
Publisher: MAC HIGHER
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Chapter 36, Problem 27P

(a)

To determine

The proof that kinetic energy is p22μ .

(b)

To determine

The approximate value of Rydberg’s coefficient.

(c)

To determine

The percent correct of ground state energy.

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Electron capture is a variant on beta-radiation.  The lightest nucleus to decay by electron capture is 7Be -- beryllium-7.  The daughter nucleus is 7Li -- lithium-7.  The electron is transformed into a massless particle (a neutrino): e − + 7 B e + ⟶ 7 L i + ν The initial electron is bound in the atom, so the beryllium mass includes the electron.  In fact, since the electron starts bound in the atom, a more-accurate statement of the nuclear reaction is probably: 7 B e ⟶ 7 L i + ν The masses are beryllium: 7.016929 u, and lithium: 7.016003 u, and refer to the neutral atom as a whole.  (Use uc and uc2 as your momentum and energy units -- but carry them along in your calculation.) The initial beryllium atom is stationary.  Calculate the speed of the final lithium nucleus in km/s. (You will make life much easier for yourself if you recognize that practically all the energy released goes into the lighter particle.  c = 300,000 km/s)
Electron capture is a variant on beta-radiation.  The lightest nucleus to decay by electron capture is 7Be -- beryllium-7.  The daughter nucleus is 7Li -- lithium-7.  The electron is transformed into a massless particle (a neutrino): e − + 7 B e + ⟶ 7 L i + ν The initial electron is bound in the atom, so the beryllium mass includes the electron.  In fact, since the electron starts bound in the atom, a more-accurate statement of the nuclear reaction is probably: 7 B e ⟶ 7 L i + ν The masses are beryllium: 7.016929 u, and lithium: 7.016003 u, and refer to the neutral atom as a whole.  (Use uc and uc2 as your momentum and energy units -- but carry them along in your calculation.) The initial beryllium atom is stationary.  Calculate the speed of the final lithium nucleus in km/s. (all the energy released goes into the lighter particle.  c = 300,000 km/s)
An iron nail has a mass of 15.0 g. What is the energy (in Joules) that would be required to break all the iron nuclei into their constituent protons and neutrons? Ignore the energy that binds the electrons to the nucleus and the energy that binds one atom to another in the structure of the metal. For simplicity, assume that all the iron nuclei are 56 Fe (atomic mass = 55.934 939 u).
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